A gas occupies 210 ml at -73°c. to have the same gas occupy 360 ml: should the temperature be increased or decreased? what is t
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The speed of Matt is 10 mph.
Doug runs 2 miles an hour faster than Matt, so let Matt’s speed equal x miles per hour. Then Doug’s speed equals x + 2 miles per hour. Each lap is one-quarter of a mile, so Doug runs 1.5 miles in the time it takes Matt to run 1.25 miles.
Rate of Matt is x
Rate of Dough is (x + 2)
Time taken by Matt is 1.25/x
Time taken by Dough is 1.25/(x + 2)
Distance covered by Matt is 1.25
Distance covered by Dough is 1.5
Dough and Matt took the same amount of time from the time Doug started, so make an equation by setting the two times in the chart equal to each other, and then solve for x:
=
1.5x = 1.25(x + 2)
1.5x = 1.25x + 2.5
0.25x = 2.5
x = 10
So Matt ran at 10 miles per hour.
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