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Dmitriy789 [7]
3 years ago
15

A coyote is looking for some food for its young. It spots a pocket mouse near a cactus and starts to track and hunt the mouse fo

r food.
In this scenario, the cactus is considered:
a. predator
b. prey
c. neither
Physics
2 answers:
Dmitrij [34]3 years ago
8 0

Answer:

c neither

Explanation:

the cactus is just kinda chillin there

makkiz [27]3 years ago
7 0

Answer:

Neither

Explanation: <em>The cactus isn't really used for anything. The coyote only saw the mouse nearby it. The coyote was only hunting for the mouse, not the cactus.</em>

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A spherical drop of water carrying a charge of 43 pC has a potential of 540 V at its surface (with V = 0 at infinity). (a) What
almond37 [142]

Explanation:

Given that,

Charge on a spherical drop of water is 43 pC

The potential at its surface is 540 V  

(a) The electric potential on the surface is given by :

V=\dfrac{kq}{r}

r is the radius of the drop

r=\dfrac{kq}{V}\\\\r=\dfrac{9\times 10^9\times 43\times 10^{-12}}{540}\\\\r=7.17\times 10^{-4}\ m

(b) Let R is the radius of the spherical drop, when two such drops of the same charge and radius combine to form a single spherical drop. ATQ,

\dfrac{4}{3}\pi r^3+\dfrac{4}{3}\pi r^3=\dfrac{4}{3}\pi R^3\\\\2r^3=R^3\\\\R=2^{1/3} r

Now the charge on the new drop is 2q. New potential is given by :

V=\dfrac{9\times 10^9\times 43\times 10^{-12}\times 2}{2^{1/3}\times 7.17\times 10^{-4}}\\\\V=856.79\ V

Hence, the radius of the drop is 7.17\times 10^{-4}\ m and the potential at the surface of the new drop is 856.79 V.

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