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OleMash [197]
2 years ago
9

The law of suggests that the orbit of planets is not circular but.

Physics
2 answers:
adoni [48]2 years ago
7 0

Newton's law of universal gravitation ... massaged and manipulated
with a lot of calculus and geometry ... predicts that closed gravitational
orbits are ellipses.  

The circle is such a precise special kind of ellipse that a circular orbit
never occurs.  The chance of it is like the chance of flipping a coin and
having it land standing up on its edge ... possible, but very improbable.

anygoal [31]2 years ago
5 0

Answer:

Kepler's 2nd law describe the shape of orbit

Explanation:

Kepler's 2nd law describe the shape of orbit

A planet's orbit's around which it revolve around the Sun is not a circle. It's an ellipse — a ring that's "flattened." The Sun (which is also called the planet's center) holds one ellipse target. A concentration is among two inner points helping to decide an ellipse's form.

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A bullet leaves a gun with a horizontal velocity of 100 m/s. Calculate the distance it would travel in 1.3 seconds.
salantis [7]

Answer:

130m

Explanation:

You just have to multiply velocity by the time traveled:

100m/s * 1.3s = 130m!

5 0
3 years ago
Read 2 more answers
How fast can a man run in miles per hour?
ExtremeBDS [4]
Depends on how well built he is probably for the average American 8 MPH
6 0
3 years ago
Which of the following is true about light waves and sound waves? A. Sound waves can move at different speeds, but light waves a
vivado [14]

Answer:

C

Explanation:

Sound waves speed up noticeably when moving through a solid or liquid, because all it is is just particles colliding; and particles are way closer together with those states of matter.

The speed of light can change when moving through different substances, but this is dependent on complicated factors such as frequency, polarization, intensity, et. cetera

The important part is that it does change speed, so your answer is C.

Hope this helps!

3 0
3 years ago
a sphere of diameter 6•0cm is moulded into a thin uniform wire of diameter 0•2mm.calculate the length of the wire in metres​
Scilla [17]

The length of the wire is 36 m.

<u>Explanation:</u>

Given, Diameter of sphere = 6 cm

We know that, radius can be found by taking the half in the diameter value. So,

       \text { sphere radius, } R=\frac{D}{2}=\frac{6}{2}=3 \mathrm{cm}=3 \times 10^{-2} \mathrm{m}

Similarly,

      \text { wire radius, } r=\frac{0.2}{2}=0.1 \mathrm{mm}=1 \times 10^{-3} \mathrm{m}

We know the below formulas,

          \text {volume of sphere}=\frac{4}{3} \times \pi \times R^{3}

          \text {volume of wire}=\pi \times r^{2} \times l

When equating both the equations, we can find length of wire as below, where \pi=\frac{22}{7}

          \frac{4}{3} \times \pi \times R^{3}=\pi \times r^{2} \times l

         \frac{4}{3} \times \frac{22}{7} \times\left(3 \times 10^{-2}\right)^{3}=\frac{22}{7} \times\left(1 \times 10^{-3}\right)^{2} \times l

The \pi value gets cancelled as common on both sides, we get

           \frac{4}{3} \times 27 \times 10^{-6}=10^{-6} \times l

The 10^{-6} value gets cancelled as common on both sides, we get

           l=4 \times 9=36 m

7 0
3 years ago
Consider electrons of kinetic energy 6.0 eV and 600 keV. For each electron, find the de Broglie wavelength, particle speed, phas
irinina [24]

Answer:

For 6.0 eV

0.5 nm, 1.45*10^6 m/s, 6.17*10^10 m/s, 1.45*10^6 m/s

For 600 eV

1.26*10^-3 nm, 2.66*10^8 m/s, 3.37*10^8 m/s, 2.66*10^8 m/s

Explanation:

See attachment for calculation

5 0
3 years ago
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