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OleMash [197]
3 years ago
9

The law of suggests that the orbit of planets is not circular but.

Physics
2 answers:
adoni [48]3 years ago
7 0

Newton's law of universal gravitation ... massaged and manipulated
with a lot of calculus and geometry ... predicts that closed gravitational
orbits are ellipses.  

The circle is such a precise special kind of ellipse that a circular orbit
never occurs.  The chance of it is like the chance of flipping a coin and
having it land standing up on its edge ... possible, but very improbable.

anygoal [31]3 years ago
5 0

Answer:

Kepler's 2nd law describe the shape of orbit

Explanation:

Kepler's 2nd law describe the shape of orbit

A planet's orbit's around which it revolve around the Sun is not a circle. It's an ellipse — a ring that's "flattened." The Sun (which is also called the planet's center) holds one ellipse target. A concentration is among two inner points helping to decide an ellipse's form.

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For a vehicle to negotiate a banked curve in poor weather conditions, where the force of friction f = 0, for a given velocity v
djverab [1.8K]

Answer:

R=240m

Explanation:

From the question we are told that:

Velocity v=25m/s

Force of friction f = 0

Angle \theta=15

Generally the equation for  Radius of curvature is mathematically given by

R=frac{v^2}{tan\theta *g}

R=frac{25^2}{tan 15 *9.81}

R=240m

7 0
3 years ago
Which statement is true of the electric field at a distant from the source of charge?
iVinArrow [24]

Answer:

A negative charge, if free to move in an electric field, will move from a low potential point to a high potential point. To move a positive charge against the electric field, work has to be done by you or a force external to the field.

Explanation:

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8 0
3 years ago
One of the harmonics on a string 1.30m long has a frequency of 15.60 Hz. The next higher harmonic has a frequency of 23.40 Hz. F
Alja [10]

Answer:

\large \boxed{\text{(a) 7.800 Hz; (b) 20.3 m/s; 40.6 m/s; 60.8 m/s}}

Explanation:

a) Fundamental frequency

A harmonic is an integral multiple of the fundamental frequency.

\dfrac{\text{23.40 Hz}}{\text{15.60 Hz}} = \dfrac{1.500}{1} \approx \dfrac{3}{2}

f = \dfrac{\text{24.30 Hz}}{3} = \textbf{7.800 Hz}

b) Wave speed

(i) Calculate the wavelength

In a  fundamental vibration, the length of the string is half the wavelength.

\begin{array}{rcl}L & = & \dfrac{\lambda}{2}\\\\\text{1.30 m} & = & \dfrac{\lambda}{2}\\\\\lambda & = & \text{2.60 m}\\\end{array}

(b) Calculate the speed s

\begin{array}{rcl}v_{1}& = & f_{1}\lambda\\& = & \text{7.800 s}^{-1} \times \text{2.60 m}\\& = & \textbf{20.3 m/s}\\\end{array}

\begin{array}{rcl}v_{2}& = & f_{2}\lambda\\& = & \text{15.60 s}^{-1} \times \text{2.60 m}\\& = & \textbf{40.6 m/s}\\\end{array}

\begin{array}{rcl}v_{3}& = & f_{3}\lambda\\& = & \text{23.40 s}^{-1} \times \text{2.60 m}\\& = & \textbf{60.8 m/s}\\\end{array}

4 0
3 years ago
WILL MARK BRAINLIEST
rodikova [14]

Answer:

152,155 J

Explanation:

115,333 + 36,822 = 152,155J

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What’s up world or people
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Hi how are you?

Are you a Libra?

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