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pogonyaev
3 years ago
7

If a quadrilateral has congruent diagonals, then it is a rectangle What is the inverse of this conditional statement?

Mathematics
1 answer:
Ann [662]3 years ago
5 0

Answer:I need a picture please

Step-by-step explanation:

You might be interested in
PLEASE HELP QUICKLY
iren [92.7K]

Answer:

The exponents of a start at n and decrease until they reach 0 . The exponents of b start at 0 and increase until they reach n

Step-by-step explanation:

The general formula for (a+b)^n is:

a^n + C_1a^{n-1}b + C_2a^{n-2}b^2 + ... + C_{n-1}a^2b^{n-2} + C_nab^{n-1} + b^n

Therefore, the exponents of a start at n and decrease until they reach 0 . The exponents of b start at 0 and increase until they reach n

7 0
3 years ago
1/3(4 + 18)-2²<br>PLIS I need help :(​
liraira [26]

Answer:

10/3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

1/3(4 + 18) - 2²

<u>Step 2: Evaluate</u>

  1. (Parenthesis) Add:                                                                                          1/3(22) - 2²
  2. Exponents:                                                                                                      1/3(22) - 4
  3. Multiply:                                                                                                           22/3 - 4
  4. Subtract:                                                                                                          10/3
5 0
3 years ago
Could anyone tell me where these numbers would go? domain or range?
Free_Kalibri [48]
Independent, x-coordinate, input, domain.
Dependent, y-coordinate, output, range.

Domain: {0.5, 1, 4, 6, 8}
Range: {1, 1.5, 10, 12, 18}
8 0
3 years ago
In simplest radical form, what are the solutions to the quadratic equation 6 = x2 – 10x?
vichka [17]

Answer:

x = 5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}

Step-by-step explanation:

We need to solve the quadratic equation

6 = x^2 -10x

Rearranging we get,

x^2-10x-6=0

Using quadratic formula to solve the quadratic equation

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a= 1, b =-10 and c=6

Putting values in the quadratic formula

x=\frac{-(-10)\pm\sqrt{(-10)^2-4(1)(-6)}}{2(1)}\\x=\frac{10\pm\sqrt{100+24}}{2}\\x=\frac{10\pm\sqrt{124}}{2}\\x=\frac{10\pm\sqrt{2*2*31}}{2}\\x=\frac{10\pm\sqrt{2^2*31}}{2}\\x=\frac{10\pm2\sqrt{31}}{2}\\x = 5\pm\sqrt{31}

So, x=5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}

3 0
3 years ago
Read 2 more answers
How do you do this question?
Mekhanik [1.2K]

Answer:

(-∞, -2), (-2, -0.618), and (1.618, 3)

Step-by-step explanation:

The red arrows indicate the regions in which the function is decreasing.

The corresponding intervals are (-∞, -0.618) and (1.618, 3),

Let's examine the intervals given.

(-∞, -2): Yes, decreasing.

(-2, -0.618): Yes, decreasing.

(-2, 0.689): No. Decreasing in (-2, -0.618) but increasing in (-0.618, 0.689).

(-1.17, 0.689): No. Decreasing in (-1.17, -0.618) but increasing

in (-0.618, 0.689).

(0.698, 71.457): No. Increasing from (0.698, 1.618), decreasing in (1.618, 3) and increasing in (3, 71.457).

(1.618, 3): Yes, decreasing.

(2.481, ∞): No. Decreasing in (2.481, 3) but increasing in (3, ∞).

The three choices that indicate a decreasing interval are (-∞, -2),

(-2, -0.618), and (1.618, 3).

3 0
3 years ago
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