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pogonyaev
3 years ago
7

If a quadrilateral has congruent diagonals, then it is a rectangle What is the inverse of this conditional statement?

Mathematics
1 answer:
Ann [662]3 years ago
5 0

Answer:I need a picture please

Step-by-step explanation:

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(03.01 MC)
vekshin1

Answer:

Option (1) will be the answer.

Step-by-step explanation:

Coordinates of the points A and B lying on the line f are (0, 2) and (2, 0) respectively.

Slope of the line f,

m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m_{1}=\frac{2-0}{0-2}

m_{1}=-1

After dilation of line f by a scale factor of 2, coordinates of A' and B' will be,

Rule for dilation,

(x, y) → (kx, ky)

Where k = scale factor

A(0, 2) → A'(0, 4)

B(2, 0) → B'(4, 0)

Slope of line f',

m_{2}=\frac{0-4}{4-0}

m_{2}=-1

Since, m_{1}=m_{2}=-1

Therefore, both the lines f and f' will be parallel.

Option (1) will be the answer.

6 0
3 years ago
75,747 rounded to the nearest hundred and ten
Hunter-Best [27]

Answer:

75,700

Step-by-step explanation:

1. 700. 747 is nearer to 700 and farther from 800.

8 0
3 years ago
Pls Help !!!!!!!!!!!!!!
Sedaia [141]

Answer:

30

Step-by-step explanation:

7 0
3 years ago
Quadrilateral KLMN is similar to quadrilateral WXYZ, Which statement about these quadrilaterals must be true?
VARVARA [1.3K]

Answer:angle nkl is congruent to angle zwx

Step-by-step explanation: it is equal so it matches

7 0
3 years ago
I need help with this
evablogger [386]

Answer:

A) (-8, -16)

B) (0, 48)

C) (-4, 0), (-12, 0)

Step-by-step explanation:

A) the vertex is the minimum y value.

extremes of a function we get by using the first derivation and solving it for y' = 0.

y = x² + 16x + 48

y' = 2x + 16 = 0

2x = -16

x = -8

so, the vertex is at x=-8.

the y value is (-8)² + 16(-8) + 48 = 64 - 128 + 48 = -16

B) is totally simple. it is f(0) or x=0. so, y is 48.

C) is the solution of the equation for y = 0.

the solution for such a quadratic equation is

x = (-b ± sqrt(b² - 4ac)) / (2a)

in our case here

a=1

b=16

c=48

x = (-16 ± sqrt(16² - 4×48)) / 2 = (-16 ± sqrt(256-192)) / 2 =

= (-16 ± sqrt(64)) / 2 = (-16 ± 8) / 2 = (-8 ± 4)

x1 = -8 + 4 = -4

x2 = -8 - 4 = -12

so the x- intercepts are (-4, 0), (-12, 0)

6 0
3 years ago
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