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guapka [62]
4 years ago
11

Is number 2 correct?

Chemistry
2 answers:
masha68 [24]4 years ago
5 0

Answer:

Looks correct to me if there's no other chemical equation involved. Also, use extra sig fig for molar mass of salt (go to 58.44g/mol) so your final answer is 0.0322 moles NaCl (or salt).

Explanation:

Ipatiy [6.2K]4 years ago
4 0

Answer:

Yes looks right to me!

Explanation:

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The concentration of NaOH is 25.00% by mass, it means that 25.00% of the mass of the solution is of NaOH. Hence:

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The equilibrium constant, Kc, for the following reaction is 4.76×10-4 at 431 K. PCl5(g) PCl3(g) + Cl2(g) When a sufficiently lar
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Answer:

Explanation:

Step 1: Data given

The equilibrium constant, Kc, for the following reaction is 4.76 * 10^-4 at 431 K

The equilibrium concentration of Cl2(g) is  0.233 M

Step 2: The balanced equation

PCl5(g)  ⇄ PCl3(g) + Cl2(g)

Step 3: The initial concentration

[PCl5]= Y M

[PCl] = 0M

[Cl2] = 0M

Step 4: Calculate the concentration at equilibrium

[PCl5] = Y + X M = Y - 0.233 M

[PCl]= XM = 0.233 M

[Cl2]= XM = 0.233 M

Step 5: Define Kc

Kc =  [Cl2]* [PCl3] / [PCl5]

4.76 * 10^-4 = 0.233² / (Y -0.233)

0.000476 = 0.05429 / (Y - 0.233)

Y - 0.233 = 0.05429 / 0.000476

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The concentration of PCl5 at the equilibrium is 114.05 M

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