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jasenka [17]
3 years ago
14

You want to make 100 mL of a 2.5 M stock solution of calcium chloride (molecular weight 110.98 g/mol). How many grams of calcium

chloride do you need to weigh out in order to make this solution? Round your answer to the nearest tenth of a gram.
Chemistry
1 answer:
Evgesh-ka [11]3 years ago
5 0

Answer:

27.7 g

Explanation:

  • 100 mL = 0.100 L

To solve this problem we use the definition of <em>molarity</em>:

  • M = mol / L

From the problem we're given M = 2.5 M and volume = 0.100 L. We use the above formula and <u>calculate the required moles of calcium chloride</u> (CaCl₂):

  • 2.5 M = moles / 0.100 L
  • moles = 0.25 moles CaCl₂

Finally we use the<em> molecular weight</em> of calcium chloride to <u>calculate the required mass</u>:

  • 0.25 moles CaCl₂ * 110.98 g/mol = 27.745 g CaCl₂

Rounding to the nearest tenth of a gram the answer is 27.7 g.

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Answer:

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Explanation:

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<em />

PV / RT = n

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1.56mol*14% = 0.22 moles of hydrogen are removed.

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Right answer is:

<h3>C) 1.3 mol</h3>

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