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3 years ago

Which sentence describes a tropical rainforest ?

Chemistry

1 answer:

kvasek [131]3 years ago

4 0

Answer is: D. it is always wet.

Tropical rainforests are rainforests that occur in areas of tropical rainforest climate, between 10 degrees north and south of the equator.

In tropical rainforest there is no dry season, all months have an average precipitation of at least 60 mm.

Tropical rainforests contain a lot animal species.

They have high levels of biodiversity, around 40% to 75% of all biotic species are in the rainforest.

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What volume, in mL, of concentrated 16 M nitric acid would you need to use in order to prepare 500.0 mL of a 0.250 M HNO3(aq) so

shtirl [24]

Given :

Initial concentration of nitric acid, $C_1 = 16\ M$ .

Final concentration of nitric acid, $C_2 = 0.250 \ M$ .

Volume of $HNO_3$ , $V _2= 500\ mL = 0.5\ L .$

To Find :

Volume needed( $V_1$ ).

Solution :

We know,

$C_1V_1 =C_2V_2\\\\16 \times V_1 = 0.250 \times 0.5 \\\\V_1 = \dfrac{0.250 \times 0.5}{16}\\\\V_1 = 0.0078125\ L = 7.8125 \ mL$

Hence, this is the required solution.

6 0

3 years ago

A night when the temperature is 22°C?

Ede4ka [16]

huh that's suspicious that's weird

4 0

3 years ago

If 251 mL of 6.0 M H2SO4 is diluted to 500. mL, what is its new molarity?

kolezko [41]

Answer:

3.0M

Explanation:

The dilution formula is:

$M_1\times V_1=M_2\times V_2$

Where M₁ and M₂ are the molar concentrations and V₁ and V₂ are the volumes of the concentrated and the diluted solutions.

Substitute:

M₁ = 6.0M

M₂ = unknown

V₁ = 251 mL

V₂ = 500. mL

$6.0M\times 251ml=M_2\times 500.ml$

Clear M₂ and compute:

$M_2=6.0M\times 251ml/500.ml\approx3.0M$

8 0

3 years ago

100 points!!!!!!!!!!!!!!!!!! how does a volcanic eruption benefit the surrounding area? A. Lava and ash bury animal habitats. B.

Shkiper50 [21]

I think it would be C) The surrounding soil can become very fertile

4 0

3 years ago

Read 2 more answers

In 2021, you were given a 100. g wine sample to verify its age. Using tritium dating you observe that the sample has 0.688 decay

nikdorinn [45]

Answer:

1984

Explanation:

Given the formula;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/2 = half life of the radioactive isotope

t= age of the wine

Ao= initial activity of the wine

A= activity of the at time = t

0.693/12.3 = 2.303/t log (5.5/0.688)

0.693/12.3 = 2.079/t

0.056 = 2.079/t

t= 2.079/0.056

t= 37 years

The wine was produced 37 years ago which means that it was produced in the year 1984

7 0

3 years ago