Answer: The zeros of the quadratic function are: 5/2+(1/2)*sqrt(31), 5/2-(1/2)*sqrt(31)
Step-by-step explanation:
The first step is to find the slope. Use the slope formula
m = (y2-y1)/(x2-x1)
The two points are (x1,y1) = (-1,5) and (x2,y2) = (2,-1)
So,
x1 = -1
y1 = 5
and
x2 = 2
y2 = -1
will be plugged into the slope formula to get...
m = (y2-y1)/(x2-x1)
m = (-1-5)/(2-(-1))
m = (-1-5)/(2+1)
m = (-6)/(3)
m = -2
The slope is -2
Use m = -2 and one of the points to find the y intercept b. I'll use the point (x,y) = (-1,5) ---> x = -1, y = 5
y = mx+b ... slope intercept form
5 = -2*(-1)+b
5 = 2+b
5-2 = 2+b-2
3 = b
b = 3
The y intercept is 3
-----------------------------------
m = -2 is the slope
b = 3 is the y intercept
Therefore y = mx+b turns into y = -2x+3 as the equation that goes through the two points
Answer:
The equivalent expression is - 25n - 2 and it matches with option D.
Step-by-step explanation:
We have to simplify and create the equivalent expression for
{- 2(- 5n + 6) + 5(2 - 7n)}
Now, {- 2(- 5n + 6) + 5(2 - 7n)}
= 10n - 12 + 10 - 35n
= - 25n - 2
Therefore, the equivalent expression is - 25n - 2 and it matches with option D. (Answer)
If the bases are the same then you can let the exponents be equal to each other. If the exponents are not the same then you will have to use logarithms to solve for x.
Y+2=2(X-0) OR Y-6=2(X-4). Either one works.
