What are the zeros of the quadratic function? f(x)=2x2+x-3
1 answer:
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Answer:
P (5 , 8)
Step-by-step explanation:
P (x,y) partition A (x₁ , y₁) B (x₂ , y₂) into ratio AM:MB = a:b = 2:1 ... a=2 , b=1
x = (bx₁ + ax₂) / (a+b)
= (1 * 3 + 2 * 6) / (2 + 1)
= 15/3
= 5
y = (by₁ + ay₂) / (a+b)
= (1 * 4 + 2 * 10) / (2 + 1)
= 24/3
= 8
P (5 , 8)
