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laiz [17]
3 years ago
7

A spacecraft starts in elliptical orbit JK (red solid curve) around some planet and transfers to elliptical orbit MN (blue solid

curve). To do so, it changes its speed at K and inserts into the circular orbit KL (dashed green curve). At L, it changes speed again to insert into elliptical orbit LM (dashed magenta curve). Finally, at M, it changes speed to insert into the final orbit MN. Find all the changes in speed.Mass of planet compared to mass of Earth: Mplanet /MEarth = 2Radius of planet: Rplanet = 5000 mia = 500 mib = 1500 mic = 200 mid = 1000 mi

Engineering
1 answer:
Aleksandr-060686 [28]3 years ago
7 0

Answer:

Speed in orbit Jk = 4.976 *10⁵m/s

Speed in orbit KL = 4.429 *10⁵ m/s

Speed in orbit LM = 5.005 * 10⁵ m/s

Explanation:

See the attached files for the calculation

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3.24 Program: Drawing a half arrow (Java) This program outputs a downwards facing arrow composed of a rectangle and a right tria
Lostsunrise [7]

Answer:

Here is the JAVA program:

import java.util.Scanner; // to get input from user

public class DrawHalfArrow{ // start of the class half arrow

public static void main(String[] args) { // starts of main() function body

    Scanner scnr = new Scanner(System.in); //reads input

int arrowBaseHeight = 0; // stores the height of arrow base

int arrowBaseWidth  = 0; // holds width of arrow base

int arrowHeadWidth = 0; // contains the width of arrow head

// prompts the user to enter arrow base height, width and arrow head width

System.out.println("Enter arrow base height: ");

arrowBaseHeight = scnr.nextInt(); // scans and reads the input as int

System.out.println("Enter arrow base width: ");

arrowBaseWidth = scnr.nextInt();

/* while loop to continue asking user for an arrow head width until the value entered is greater than the value of arrow base width */

while (arrowHeadWidth <= arrowBaseWidth) {

    System.out.println("Enter arrow head width: ");

    arrowHeadWidth = scnr.nextInt(); }

//start of the nested loop

//outer loop iterates a number of times equal to the height of the arrow base

 for (int i = 0; i < arrowBaseHeight; i++) {

//inner loop prints the stars asterisks

      for (int j = 0; j <arrowBaseWidth; j++) {

          System.out.print("*");        } //displays stars

          System.out.println();          }

//temporary variable to hold arrowhead width value

int k = arrowHeadWidth;

//outer loop to iterate no of times equal to the height of the arrow head

for (int i = 1; i <= arrowHeadWidth; i++)

{     for(int j = k; j > 0; j--)     {//inner loop to print stars

       System.out.print("*");    } //displays stars

   k = k - 1;

   System.out.println(); } } } // continues to add more asterisks for new line

Explanation:

The program asks to enter the height of the arrow base, width of the arrow base and the width of arrow head. When asking to enter the width of the arrow head, a condition is checked that the arrow head width arrowHeadWidth should be less than or equal to width of arrow base arrowBaseWidth. The while loop keeps iterating until the user enters the arrow head width larger than the value of arrow base width.

The loop is used to output an arrow base of height arrowBaseHeight. So point (1) is satisfied.

The nested loop is being used which as a whole outputs an arrow base of width arrowBaseWidth. The inner loop draws the stars and forms the base width of the arrow, and the outer loop iterates a number of times equal to the height of the arrow. So (2) is satisfied.

A temporary variable k is used to hold the original value of arrowHeadWidth so that it keeps safe when modification is done.

The last nested loop is used to output an arrow head of width arrowHeadWidth. The inner loop forms the arrow head and prints the stars needed to form an arrow head. So (3) is satisfied.

The value of temporary variable k is decreased by 1 so the next time it enters  the nested for loop it will be one asterisk lesser.

The screenshot of output is attached.

8 0
4 years ago
A 0.01 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender? select
Nataly_w [17]

Answer:

Option D

H_o equals 0.5 H_a less than 0.5

Explanation:

Information given

N=144

X=66

P=\frac {x}{n}=66/144= 0.458333\approx 0.46

The hypothesis

Null hypothesis

Probability, p =0.5

H_o: p =0.5

Alternative hypothesis

Probability, p<0.5

H_a: p

5 0
4 years ago
What kind of robot should i make
schepotkina [342]

Answer:

It really depends on what you want it to do. I would make one that does chores around the house so I don't have to.

Explanation:

4 0
2 years ago
The heavier an atomic nucleus gets, the less energy the star is able to extract from it through nuclear fusion. When it gets to
Slav-nsk [51]

Answer:

Iron

Explanation:

Once a star starts fusing iron in its core it gives off very large amounts of energy. Also helium, hydrogen, carbon, oxygen, and silicon still exist in the star in different shells while fusin is taking place at different parts of the star. Right at the surface, hydrogen continues to fuse to helium, as e go further down helium is fusing to carbon and oxygen; right inside the core we have silicon that is fusing with iron. At this point, Iron being of stable atomic structure and quite heavier will no longer be fused into anything because of the quite large amounts of energy and force required to fuse iron atoms. The process comes to a standstill at this point.

6 0
3 years ago
When you apply for your driver license, you consent to take a ____ test when asked to do so by a law enforcement officer. memory
n200080 [17]

Answer:

Driving test

Explanation:

Usually according to laws in countries worldwide, to be licenced to drive, one is required to go through a driving school to learn the ethics and rules of driving.

4 0
2 years ago
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