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krok68 [10]
3 years ago
12

I was grumpy with her when she came over because she forgot something we planned to do.I offered to pick her up down town while

her car was being worked on. We took the kids to the zoo. There were a few moments when I complained about the whole day being gone. For the most part I tried to stay positive, so she did not feel bad about me giving up the day. I told my mom I would help her do her nails. She came over and instead of playing with the kids before bed I helped her get her nails done.Thanked her for helping with dinner. Called and had a nice chat to start the day.a. What was the ratio of confirming to disconfirming messages that I sent? (Note: If you find that your ration of confirming to disconfirming is about equal, you are in trouble. Research shows that it takes between 5 and 16 confirming messages to make up for one disconfirming message!)
Engineering
1 answer:
WINSTONCH [101]3 years ago
7 0

Answer: confirming messages 6, Discomforming message 2 the ratio was 6:2

Explanation: Confirming Messages help show Confirming responses that you value the person, opinions and their interactions. Confirming messages shows the other person that you are listening to him/her, that you value what they say.

e.g 1. Picking her up downtown

2. Taking the kids to the zoo

3. Staying positive when with her

4, the mom helping with the kids

5. Fixing the mum nail's

6. Calling and having a nice chat

Discomforming messages usually affects a person’s sense of self-worth negatively.

E.g being grumpy because she forgot their plans, complaints made while at the zoo

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What is the subtotal for the building materials in the bill? The subtotal should be the cost of the materials only. Don't add ta
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Answer:

Cost before adding taxes and incorporating variations

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4 years ago
The closed tank of a fire engine is partly filled with water, the air space above being under pressure. A 6 cm bore connected to
skelet666 [1.2K]

Answer:

The air pressure in the tank is 53.9 kN/m^{2}

Solution:

As per the question:

Discharge rate, Q = 20 litres/ sec = 0.02\ m^{3}/s

(Since, 1 litre = 10^{-3} m^{3})

Diameter of the bore, d = 6 cm = 0.06 m

Head loss due to friction, H_{loss} = 45 cm = 0.45\ m

Height, h_{roof} = 2.5\ m

Now,

The velocity in the bore is given by:

v = \frac{Q}{\pi (\frac{d}{2})^{2}}

v = \frac{0.02}{\pi (\frac{0.06}{2})^{2}} = 7.07\ m/s

Now, using Bernoulli's eqn:

\frac{P}{\rho g} + \frac{v^{2}}{2g} + h = k                  (1)

The velocity head is given by:

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\frac{P_{tank}}{\rho g} + \frac{v_{tank}^{2}}{2g} + h_{tank} = \frac{P_{roof}}{\rho g} + \frac{v_{tank}^{2}}{2g} + h_{roof} + H_{loss}

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P_{tank} = 5.5\times \rho \times g

P_{tank} = 5.5\times 1\times 9.8 = 53.9\ kN/m^{2}

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Answer:

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