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iragen [17]
4 years ago
14

The table below shows the distance d(t) in feet that an object travels in t seconds:

Physics
2 answers:
vazorg [7]4 years ago
8 0
The rate of change of d(t) at t = 2 and t = 6 is the ratio between the change of distance (difference between the distances) to the time elapsed. That is,
                                   r = (576 - 64) / (6 - 2) = 128 ft /s
The rate of change is equal to 128 ft/s and this represents the average speed at this time interval. 
vlabodo [156]4 years ago
5 0

Answer:

11111111111

Explanation:

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Which of the following will cause an increase in gas pressure in a closed container?
kati45 [8]
D. Both b and c is the answer
7 0
3 years ago
Arjun told to his friend that " Q can form a virtual image larger than the object by refraction." What is "Q"?
nadezda [96]

Q is a concave mirror.

Explanation:

The image formed by a concave mirror is observed to be virtual, erect and larger than the object.

7 0
2 years ago
A Decay Chain
Strike441 [17]

Answer : The energy released in first step of thorium-232 decay chain is 7.974\times 10^{-13}J

Explanation :

First we have to calculate the mass defect (\Delta m).

The balanced reaction is,

^{232}Th\rightarrow ^{228}Ra+^{4}He

Mass defect = Sum of mass of product - sum of mass of reactants

\Delta m=(\text{Mass of Ra}+\text{Mass of He})-(\text{Mass of Th})

\Delta m=(228.0301069+4.002602)-(232.038054)=5.34\times 10^{-3}amu=8.86\times 10^{-30}kg

conversion used : (1amu=1.66\times 10^{-27}kg)

Now we have to calculate the energy released.

Energy=\Delta m\times (c)^2

Energy=(8.86\times 10^{-30}kg)\times (3\times 10^8m/s)^2

Energy=7.974\times 10^{-13}J

The energy released is 7.974\times 10^{-13}J

Therefore, the energy released in first step of thorium-232 decay chain is 7.974\times 10^{-13}J

7 0
3 years ago
A. According to theory, the period T of a simple pendulum is T = 2????√ ???? ???? a. If ???? is measured as ???? = 1.40 ± 0.01 m
salantis [7]

Answer:

a)         T = (2,375 ± 0.008) s , b) When comparing this interval with the experimental value we see that it is within the possible theoretical values.

Explanation:

a) The period of a simple pendulum is

         T = 2π √ L / g

Let's calculate

         T = 2π √1.40 / 9.8

         T = 2.3748 s

The uncertainty of the period is

         ΔT = dT / dL ΔL

         ΔT = 2π ½ √g/L   1/g  ΔL

         ΔT = π/g √g/L   ΔL

         ΔT = π/9.8 √9.8/1.4    0.01

         ΔT = 0.008 s

The result for the period is

        T = (2,375 ± 0.008) s

b) the experimental measure was T = 2.39 s ± 0.01 s

The theoretical value is comprised in a range of [2,367, 2,387] when we approximate this measure according to the significant figures the interval remains [2,37, 2,39].

When comparing this interval with the experimental value we see that it is within the possible theoretical values.

6 0
4 years ago
What is the product of mass and velocity called?
Crank
The product of mass and velocity is momentum. P=mv. The 'P' in the equation stands for momentum.
3 0
3 years ago
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