All categories

3 years ago

How does an atom of strontium 88 become a strontium ion with a+2 charge ?

Physics

2 answers:

Oksana_A [137]3 years ago

7 0

<u>Answer:</u>

Strontium atom loses 2 electrons to become an ion.

<u>Explanation:</u>

Strontium (an Alkaline Earth metal) is the 38th element found in the Group 2 of the periodic table.

A Strontium atom has same number of electrons as its protons. It has a +2 electronegativity because it belongs to group 2 of the periodic table so it has the tendency to lose 2 electrons to form a positive ion.

Therefor, Strontium atom loses 2 electrons to become an ion with 2 electrons lesser than its atom.

levacccp [35]3 years ago

5 0

Answer:

The atom loses 2 electrons, to make a total of 36

Explanation:

You might be interested in

The speed of light is the fastest in which medium

wlad13 [49]

In vacuum, going at 2.99×10^8 m/s.

3 0

3 years ago

Read 2 more answers

A ball was rolling downhill at 2 m/s. After 5s, it was rolling at 90 m/s. What is its acceleration?

olga55 [171]

Answer:

17.6 m/s²

Explanation:

Given:

$v_{f}$ = 90 m/s (final velocity)

$v_{i}$ = 2 m/s (initial velocity)

Δt = 5s (change in time)

The formula for acceleration is:

$a_{avg}$ = Δv / Δt

We can find Δv by doing

Δv = $v_{f}$ - $v_{i}$

Replace the values

Δv = 90m/s - 2m/s

Δv= 88m/s

Using the equation from earlier, we can find the acceleration by dividing the average velocity by time.

$a_{avg}$ = Δv / Δt

$a_{avg}$ = $\frac{88m/s}{5/s}$

acceleration = 17.6 $m/s^{2}$

4 0

3 years ago

Assume that in 2010 the United States will need 2.0×1012 watts of electric power produced by thousands of 1000 MW power plants.

Alex73 [517]

Answer:

1752.14 tonnes per year.

Explanation:

To solve this exercise it is necessary to apply the concepts related to power consumption and power production.

By conservation of energy we know that:

$\dot{P} = \bar{P}$

Where,

$\dot{P} =$ Production of Power

$\bar{P} =$ Consumption of power

Where the production of power would be,

$\dot{P} = m \dot{E}\eta$

Where,

m = Total mass required

$\dot{E} =$ Energy per Kilogram

$\eta =$ Efficiency

The problem gives us the aforementioned values under a production efficiency of 45%, that is,

$\dot{P} = \bar{P}$

$m \dot{E}\eta = \bar{P}$

Replacing the values we have,

$m(8*10^13)(0.45) = 2*10^{12}$

Solving for m,

$m = \frac{ 2*10^{12}}{(8*10^13)(0.45)}$

$m = 0.0556 \frac{kg}{s}$

We have the mass in kilograms and the time in seconds, we need to transform this to tons per year, then,

$m = 0.556\frac{kg}{s}*(\frac{3.1536*10^7s}{1year})(\frac{1ton}{1000kg})$

$m = 1752.14$ tonnes per year.

8 0

3 years ago

If we attach a heavy ball of mass 22 kg at the end of the first rod (the one with the circular cross section), how much would it

RUDIKE [14]

Explanation:

Below are attachments containing the complete question and solution.

6 0

3 years ago

Calculate the average speed of a car between 0 And 10 second give the unit

Dmitrij [34]

Answer:

I think the distance should be given in the question because the formula for getting the

average speed= total distance/total time taken

5 0

4 years ago