The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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I assume you happen to mean, what is the formula for a circle.
The formula is:
A=
120 dollars minus the 35 dollar flat fee = 85 dollars. divide the 85 dollars by 20 to see how many hours they played. 85 divided by 20 = 4.25. they played 4 and 1/4 hours:)
We can simplify 15/3 to 5.
N/6 = 5. Then multiply both sides of the equation by 6, giving us N = 30.
Do you mean as a fraction?