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3 years ago

Write the converse of this statement.

Mathematics

2 answers:

FromTheMoon [43]3 years ago

8 0

Answer:

If they are not equal, then the 2 's supplementary

Step-by-step explanation:

vichka [17]3 years ago

7 0

If they are not equal, then the 2's supplementary

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What is the approximate surface area of a sphere with a circumference of 37.68

sergij07 [2.7K]

We must find the radius so we can plug this into the formula for surface area.

Circumference = $2 \pi r$
$37.68 = 2 \pi r \\ r = 37.68/2 \pi$

We are going to plug this in as our radius for the most accurate answer.

The surface area of a sphere is $4 \pi r^{2}$

Surface Area = $4 \pi ( \frac{37.68}{2 \pi }) ^{2}$ ≈ 451.93 units

6 0

3 years ago

LCM of 4/6 and 4/8????

Svet_ta [14]

Answer:

24 is the LCM of 4,6,8. I think thats what your looking for.

Hope this helps!

Step-by-step explanation:

5 0

2 years ago

3. If a ladder is x feet long, how high up a wall can it safely reach?

sineoko [7]

Answer:

xsin∅

Step-by-step explanation:

If the ladder is x foot long, and it can safely make a maximum angle ∅ with the floor, then, the maximum height it can reach will be xsin∅

6 0

3 years ago

12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests

Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that $p = 0.12$ .

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so $n = 18$

This probability is:

$P = P(X = 0) + P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{18,0}.(0.12)^{0}.(0.88)^{18} = 0.1002$

$P(X = 1) = C_{18,1}.(0.12)^{1}.(0.88)^{17} = 0.2458$

$P = P(X = 0) + P(X = 1) = 0.1002 + 0.2458 = 0.3460$

There is a 34.60% probability that 0 or 1 of them is nearsighted.

5 0

3 years ago

At a rate of 4%, you paid $144.00 in interest over a two-year period. What was the original amount of your loan?

baherus [9]

Principal is the same as original amount.
1. You convert the rate % to a decimal number. (divide by 100) 

2. Substitute: 

P = 144 / (.04 x 2) 

3. Solve: 

P = 144 / .08 
P = 1,800 

4. Your answer is $1,800

6 0

3 years ago