Which equation represents a line with a slope of -2/3 that passes through point (5, -2)?
1 answer:
Answer:
c)
Step-by-step explanation:
−2 = −⅔[5] + b
−3⅓
1⅓ = b
y = −⅔x + 1⅓
Then convert to Standard Form:
y = −⅔x + 1⅓
+⅔x + ⅔x
__________
⅔x + y = 1⅓ [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]
3[⅔x + y = 1⅓]
* 1⅓ = 4⁄3
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Answer:
x=-1 and y=-5
Step-by-step explanation:
ሰላም!
Given expressions let them given as two equations
- y=2+7x....... equation (1)
- -2x+6y=-28..... equation (2)
Thus, substitute y=2+7x into equation (2)
simplify it
subtract 12 from both sides
divide both sides by 40
Therefore, as we get the value of x=-1 substitute it to equation (1) and solve for variable y
To be more sure make a cross check on both of the two expressions
Thus,
1) y=2+7x .... substitute y=-5 and x=-1 and check if it is equal
-5=2+7(-1)
-5=2-5
-5=-5
2)-2x+6y=-28... substitute and check
-2(-1)+6(-5)=-28
2-30=-28... (-a)(-b)=ab
-28=-28
Hope it helps!
Given a polynomial and a point
, we have that
We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of
Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be
To fix the correct value for a, we impose :
And so we must impose
So, the function we're looking for is