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2 years ago

How do you solve A=πr² for r?

Mathematics

1 answer:

gogolik [260]2 years ago

7 0

Answer:

$\sqrt{\frac{A}{\pi } } =r$

Step-by-step explanation:

$A=\pi r^2$

$\frac{A}{\pi } =r^2$

$\sqrt{\frac{A}{\pi } } =r$

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Y = 2/3 when x = 0.2

azamat

Please explain some more:)

4 0

2 years ago

the population of a town in 1995 was 60,000. the population increased by 25% in 2007.find the population in 2007.

mixer [17]

Answer:

80,000

Step-by-step explanation:

1/4(25%)×60,000=20,000

20,000+60,000=80,000

4 0

2 years ago

The function in Exercise represents the rate of flow of money in dollars per year. Assume a 10-year period at 8% compounded cont

anzhelika [568]

Answer:

a) The present value is 688.64 $

b) The accumulated amount is 1532.60 $

Step-by-step explanation:

a) The preset value equation is given by this formula:

$P=\int^{T}_{0}f(t)e^{-rt}dt$

where:

T is the period in years (T = 10 years)
r is the annual interest rate (r=0.08)

So we have:

$P=\int^{T}_{0}(0.01t+100)e^{-rt}dt$

Now we just need to solve this integral.

$P=\int^{T}_{0}0.01te^{-rt}dt+\int^{T}_{0}100e^{-rt}dt$

$P=e^{-0.08t}(-1.56-0.13t)|^{10}_{0}+1250e^{-0.08t}|^{10}_{0}$

$P=0.30+688.34=688.64 $$

The present value is 688.64 $

b) The accumulated amount of money flow formula is:

$A=e^{r\tau}\int^{T}_{0}f(t)e^{-rt}dt$

We have the same equation but whit a term that depends of τ, in our case it is 10.

So we have:

$A=e^{r\tau}\int^{T}_{0}(0.01t+100)e^{-rt}dt=e^{0.08\cdot 10}P$

$A=e^{0.08\cdot 10}688.64=1532.60 $$

The accumulated amount is 1532.60 $

Have a nice day!

6 0

3 years ago

Write the equation of the circle with the given center and radius.

34kurt

Step-by-step explanation:

The standard equation of a circle is $(x - h)^2 + (y - k)^2 = r^2$

Center = (h, k)

Center = (0,2)

h = 0

k = 2

r = 5

$(x - h)^2 + (y - k)^2 = r^2$

$(x - 0)^2 + (y - 2)^2 = 5^2$

Center = (-4,-5)

h = -4

k = -5

r = $\sqrt{2}$

$(x - h)^2 + (y - k)^2 = r^2$

$(x - (-4))^2 + (y - (-5))^2 = \sqrt{2}^2$

$(x + 4))^2 + (y + 5))^2 = \sqrt{2}^2$

Center =(-1,3)

h = -1

k = 3

r = 8

$(x - h)^2 + (y - k)^2 = r^2$

$(x - (-1))^2 + (y - 3)^2 = 8^2$

$(x + 1)^2 + (y - 3)^2 = 8^2$

Center: (9,0)

h = 9

k = 0

r = $\sqrt{3}$

$(x - h)^2 + (y - k)^2 = r^2$

$(x - 9)^2 + (y - 0)^2 = \sqrt{3}^2$

4 0

3 years ago

Please help me, i will mark brainliest

user100 [1]

Answer:

B, C, E

Step-by-step explanation:

6 0

2 years ago

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