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Anvisha [2.4K]
3 years ago
13

What causes the wind? A.The Earths orbit around the sun B.The Earths rotation on its axis C.The layers of the Earths atmosphere

d. Uneven heating by the sun
Chemistry
2 answers:
VMariaS [17]3 years ago
6 0

Answer:

Uneaven hearing by the sun

Explanation:

Igoryamba3 years ago
3 0
A the earths orbit around the sun.
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If the melted lead got hot enough to vaporize, how much energy would it have taken to vaporize 21
arsen [322]

Answer:

18 KJ

Explanation:

Data Given:

mass of Lead (m) = 21 g

Heat taken for vaporization (Q) = ?

Solution:

This problem is related to phase change and latent heat of vaporization.

Latent heat of vaporization is the amount of heat taken to convert one mole of substance at its boiling point to its vapor.

So, Latent heat of vaporization of lead has a constant value

Latent heat of vaporization of lead = 177.7 KJ/mol

Formula used

Q = m x Lv. . . . . (1)

where

Lv = specific latent heat of vaporization

here the value for latent heat of vaporization is for mole so instead of mass we will use moles in formula.

So,

Q = no. of mol x Lv. . . . . (2)

first find no. of moles for 21 g of lead

                  no. of moles = mass in grams / molar mass . . . . . . (3)

molar mass of  lead (Pb) = 207 g/mol

put values in equation 3

                      no. of moles = 21g / 207 g/mol

                      no. of moles = 0.101 mol

so,

number of moles of lead (Pb) = 0.101 mol

Put values in the eq.2

                      Q = 0.101 mol x 177.7 KJ/mol

                      Q = 18 kJ

So, 18KJ of heat is taken to vaporize 21 g of lead (Pb)

5 0
3 years ago
Cyclopropane and propylene isomers both have the formula c3h6. based on the molecular structures shown, which of these isomers w
Hoochie [10]

The measure of randomness or uncertainty  of the substance is known as the entropy of the substance.

Under the standard state, the entropy of one mole of substance is known as its standard molar entropy.

The structure of cyclopropane and propylene is shown in the attached image.

Since, the structure of propylene is an open chain structure thus, possessing high randomness. Whereas the structure of cyclopropane is ring (closed) structure and thus, not that much free to move and has less randomness.

Hence, the structure of propylene will have the higher standard molar entropy.


7 0
3 years ago
A 36.41-g sample of calcium carbonate (CaC O 3 )
Lunna [17]
M(O) = m(CaCO₃) - m(Ca) - m(C).
m(O) = 36.41 g - 14.58 g - 4.36 g.
m(O) = 17.47 g.
ω(Ca) = m(Ca) ÷ m(CaCO₃) · 100%.
ω(Ca) = 14.58 g ÷ 36.41 g · 100%.
ω(Ca) = 40 %; mass percent of calcium.
ω(C) = m(C) ÷ m(CaCO₃) · 100%.
ω(C) = 4.36 g ÷ 36.41 g · 100%
ω(C) = 12%; mass percent of carbon.
ω(O) = 100% - ω(Ca) - ω(C).
ω(O) = 100% - 40% - 12%.
ω(O) = 48%; mass percent of oxygen.
7 0
3 years ago
Mass is:
ikadub [295]

Answer:

How much an object weighs is the answer

6 0
3 years ago
Read 2 more answers
Hey, please could someone answer this?
pav-90 [236]
Carbon dioxide is the other product created.
5 0
2 years ago
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