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maks197457 [2]
4 years ago
14

A nitrogen atom and an oxygen atom combine chemically to form nitric oxide. what is nitric oxide?

Chemistry
1 answer:
ExtremeBDS [4]4 years ago
5 0
Nitric oxide is a colorless gas with the formula NO. It is one of the principal oxides of nitrogen. Nitric oxide is a free radical, i.e., it has an unpaired electron, which is sometimes denoted by a dot in its chemical formula
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C.) protons , the nucleus contains 2 subatomic particles , one protons & neutrons ( protons have a + charge & neutrons have no electrical charge
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How does cardon enter the soil
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Answer:Carbon enters the soil through the decomposition of organic material. When plants die or leaves fall off of trees, for example, they fall to the soil

Explanation:

4 0
2 years ago
alculate the pH of the solution, upon addition of 0.035 mol of NaOH to the original buffer. Express your answer using two decima
svetlana [45]

A 1.0-L buffer solution contains 0.100 mol  HC2H3O2 and 0.100 mol  NaC2H3O2. The value of Ka for HC2H3O2 is 1.8×10−5.

Calculate the pH of the solution, upon addition of 0.035 mol of NaOH to the original buffer.

Answer:

The pH of this solution = 5.06  

Explanation:

Given that:

number of moles of CH3COOH = 0.100 mol

volume of the buffer solution = 1.0 L

number of moles of NaC2H3O2 = 0.100 mol

The objective is to Calculate the pH of the solution, upon addition of 0.035 mol of NaOH to the original buffer.

we know that concentration in mole = Molarity/volume

Then concentration of [CH3COOH] = \mathtt{ \dfrac{0.100  \ mol}{ 1.0  \  L }}  = 0.10 M

The chemical equation for this reaction is :

\mathtt{CH_3COOH + OH^- \to CH_3COO^- + H_2O}

The conjugate base is CH3COO⁻

The concentration of the conjugate base [CH3COO⁻] is  = \mathtt{ \dfrac{0.100  \ mol}{ 1.0  \  L }}  

= 0.10 M

where the pka (acid dissociation constant)for CH3COOH = 4.74

If 0.035 mol of NaOH is added  to the original buffer, the concentration of NaOH added will be = \mathtt{ \dfrac{0.035  \ mol}{ 1.0  \  L }} = 0.035 M

The ICE Table for the above reaction can be constructed as follows:

                  \mathtt{CH_3COOH \ \ \   +  \ \ \ \ OH^-  \ \ \to \ \ CH_3COO^-  \ \ \ + \ \ \  H_2O}

Initial             0.10               0.035         0.10                  -

Change        -0.035          -0.035       + 0.035              -

Equilibrium    0.065              0              0.135               -

By using  Henderson-Hasselbalch equation:

The pH of this solution = pKa + log \mathtt{\dfrac{CH_3COO^-}{CH_3COOH}}

The pH of this solution = 4.74 + log \mathtt{\dfrac{0.135}{0.065}}

The pH of this solution = 4.74 + log (2.076923077 )

The pH of this solution = 4.74 + 0.3174

The pH of this solution = 5.0574

The pH of this solution = 5.06    to two decimal places

7 0
3 years ago
A car travels 75 mi/hr. How many hours will it take to travel 837 km? (Pick the answer closest to the correct answer,
nlexa [21]

Answer:

6.9 hours

Explanation:

In order to solve this problem we'll<u> convert 837 km to miles</u> (another option would be to convert 75 mi/hr to km/hr). To make said conversion we'll use the given <em>conversion factor</em>:

  • 837 km * \frac{1mi}{1.61km} = 519.88 mi

Finally we <u>calculate the time required to travel said distance</u> at a constant speed of 75 mi/hr:

  • 519.88 mi ÷ 75 mi/hr = 6.9 hr
5 0
3 years ago
All I know is that the answer isn't c.....
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B. Object B is the right choice
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