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Hitman42 [59]
2 years ago
15

On hot days, you may have noticed that potato chip bags seem to "inflate", even though they have not been opened. If I have a 25

0 mL bag at a temperature of 19C, and I leave it in my car which has a temperature of 60C, what will the new volume of the bag be? (round your answer to the nearest tenth)
Chemistry
1 answer:
Slav-nsk [51]2 years ago
7 0

The new volume of the bag will be 789.5 mL.

<u>Explanation:</u>

As per the Charles law, at constant pressure the volume of the gas is directly related to its temperature in Kelvin (K). That is as the temperature increases, the gas expands and vice-versa.

$\frac{V1}{T1} = \frac{V2}{T2}\\

V1 = 250 ml

V2 = ?

T1 = 19° C

T2 = 60° C

Now we have to rewrite the equation to get the new volume as,

V2 = $\frac{V1T2}{T1}

    =$\frac{250\times60}{19}

<em>     </em>= 789.47 ≈ 789.5 ml.

So the new volume of the bag will be 789.5 mL.

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Explanation:

Step 1: Data given

Heat of combustion of ethanol = 326.7 kcal/mol

The heat of combustion of octane =  1.308*10³ kcal/mol

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Step 2: Calculate moles octane

Moles octane = mass octane / molar mass octane

Moles octane = 463 grams / 114.23 g/mol

Moles octane = 4.05 moles

Step 3: Calculate energy of combustion of 4.05 moles octane

Combustion of 1 mol octane gives us: 1.308 * 10³ kcal/mol

Combustion of 4.05 moles octane gives us 4.05 * 1.308 * 10³ kcal/mol = <u>5.30 * 10³ kcal</u>

This means the combustion reaction of 463 grams of octane gives us 5.30 * 10³ kcal

Step 4:

Heat of combustion of ethanol = 326.7 kcal/mol

OR in words: combustion of 1 mol ethanol gives us 326.7 kcal energy

Moles ethanol = 463 grams / 46.07 g/mol

Moles ethanol = 10.05 moles

Since combustion of 1 mol ethanol gives us 326.7 kcal

10.05 moles ethanol will give us = 10.05 * 326.7 = 3283.3 kcal = <u>3.28 * 10³ kcal</u>

<u />

5.30 * 10³ kcal > 3.28 * 10³ kcal

This means 463 grams of ethanol would provide less amount of energy

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3 years ago
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