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AveGali [126]
3 years ago
9

WILL AWARD BRAINLIEST! I NEED HELP PLEASE! Match the states of matter for each of the five lines below.

Chemistry
2 answers:
KonstantinChe [14]3 years ago
5 0

Answer:

see explanations

Explanation:

The graphic is the heating curve for water. Note that it is divided into 5 distinct heat flow segments. The segments with changing slopes are single phase segments with changes in temperature values. From left to right segment A is solid ice being warmed to it's melting point. Segment B is the melting segment in which 2 phases are in contact (solid + liquid). Note that addition of heat does not change the temperature. Segment C is warming of the liquid (single phase) up to its boiling point. At the boiling point the liquid begins to pass into the gas phase and again 2 phases are in contact; i.e., liquid & gas. Note again when two phases are in contact no temperature change occurs. Finally, segment E is the heating of the pure, single phase gas.

In summary ...

Segment A => heating single phase (solid) ice up to melting pt.

Segment B => melting of ice => 2 phases in contact (s & l) ΔT = ∅.

Segment C => heating single phase (liquid) water up to boiling pt.

Segment D => boiling of liquid => 2 phases in contact (l & g). ΔT = ∅.

Segment E => heating single phase (steam) up to desired temperature.

For what it's worth, the equation for the segments that show increasing temperature values is q = mcΔT (m= mass, c = specific heat & ΔT temp change.

The segments with zero slopes (horizontal lines) are defined by equations  q = m·ΔHₓ where m = mass & ΔHₓ = heat of fusion (a constant = 335 j/g). The same is true for the line at 100°C where q = m·ΔH(v) where m = mass & ΔH(v) is the heat of vaporization (a constant = 2259 j/g.

Calculations involve calculating the amount heat transfer for each segment individually and then adding the heat values to obtain the total heat transfer.

If you need more instruction on this topic, kick back a note and I'll try to help clarify. Good Luck, Doc :-)

damaskus [11]3 years ago
5 0

Answer:

Picture attached has answers

Explanation:

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¿la densidad de una solución es mayor o menor al agregar agua?
andreev551 [17]

Answer:

La densidad experimenta una disminución

Explanation:

Hola!

En este caso, debemos recordar que la adición de agua incrementa el volumen donde se encuentra un soluto disuelto, el cual posee una cantidad de materia constante. De este modo, sabiendo que la densidad es:

\rho =\frac{m}{V}

Al incrementar el denominador (volumen), la densidad experimenta una disminución, al estar en relación inversamente proporcional.

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3 years ago
Calculate OH- given H3 O+ = 1.40 *10^-4 M
vova2212 [387]

3.16 X 10^-11 M is the [OH-] concentration when H3O+ = 1.40 *10^-4 M.

Explanation:

data given:

H30+= 1.40 X 10^-4 M\

Henderson Hasslebalch equation to calculate pH=

pH = -log10(H30+)

putting the values in the equation:

pH = -log 10(1.40 X 10^-4 M)

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The OH- concentration from the pOH by the equation:

pOH = -log10[OH-]

10.5= -log10[OH-]

[OH-] = 10^-10.5

[OH-]  = 3.16 X 10^-11 is the concentration of OH ions when hydronium ion concentration is 1.40 *10^-4 M.

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After he finished his work, Mendeleev predicted _____.
Alex17521 [72]

Answer:

the properties of three undiscovered elements  is the correct answer.

Explanation:

After he completed his work Mendeleev predicted the properties of the undiscovered elements.

In the year 1871, Dmitri Mendeleev predicted the detailed existence and the properties of the three elements that are undiscovered and he gained tremendous fame.

He left the gap in the table to put the elements which are not identified at that time and by glancing at the physical and chemical properties of an element next to the gap, Mendeleev could predict the properties of the not discovered elements.

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