1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kirza4 [7]
3 years ago
11

Classify the following statements regarding the law of mass conservation as true or false.

Chemistry
1 answer:
Ahat [919]3 years ago
8 0
True true false true
You might be interested in
Help solve this page please
AURORKA [14]

Answer:

man, i have the same problem, i don't know hpw to solve this

8 0
2 years ago
If a reaction mixture initially contains 0.168 MSO2Cl2, what is the equilibrium concentration of Cl2 at 227 ∘C?
Semenov [28]

Answer:

see explanation below

Explanation:

The question is incomplete. Here's the complete question:

<em>Consider the following reaction: </em>

<em>SO2Cl2 -----> SO2(g) + Cl2(g) </em>

<em>Kc= 2.99 x 10^-7 at 227 degrees celcius </em>

<em>If a reaction mixture initially contains 0.168 MSO2Cl2, what is the equilibrium concentration of Cl2 at 227 ∘C?</em>

This is a problem of equilibrium, therefore, we need to solve this using the expression of equilibrium constant. To do that, we need to wirte an ICE chart and solve from there:

       SOCl2 ---------> SO2 + Cl2     Kc = 2.99x10⁻⁷

i)       0.168                  0        0

c)         -x                    +x       +x

e)     0.168-x                x         x

Writting the Kc expression:

Kc = [SO2] [Cl2] / [SOCl2]

Replacing the values from the chart:

2.99x10⁻⁷ = x² / 0.168 - x

However, Kc is a very very small value, therefore, we can assume that the value of "x" would be very small too, and we can neglect the 0.168-x and just round it to 0.168:

2.99x10⁻⁷ = x²/0.168

2.99x10⁻⁷ * 0.168 = x²

√5.02x10⁻⁸ = x

x = 2.24x10⁻⁴ M

This means then, that the concentration of Cl2 in equilibrium would be:

<em>[Cl₂] = 2.24x10⁻⁴ M</em>

5 0
3 years ago
Calculate the oxidation number of the iodine (I) in each compound: HIO4 = I2 = NaI = HIO3 =
Makovka662 [10]
1) in periodic acid (HIO₄), iodine has oxidation number +7, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 4 · (-2) = 0.
x = +7.

2) in molecule of iodine (I₂), iodine has oxidation number 0, because iodine is nonpolar molecule.

3) in sodium iodide (NaI), iodine has oxidation number -1, sodium has oxidation number +1:
+1 + x = 0.
x = -1.

4) in iodic acid (HIO₃), iodine has oxidation number +5, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 3 · (-2) = 0.
x = +5.
8 0
3 years ago
Read 2 more answers
If the mass of reactants equals 100g, then the mass of the products would be equal to_______?
ioda
The answer would be A, 100g since it’s equal
7 0
1 year ago
Read 2 more answers
The solubility of a gas in a liquid increases with increasing pressure. To understand the above statement, consider a familiar e
weeeeeb [17]

Answer:

gukyfkuyk

Explanation:

5 0
3 years ago
Read 2 more answers
Other questions:
  • What best describes the path of the gas particles in a given
    15·1 answer
  • HELP!<br><br> Why does heat move from an area of higher energy to an area with lower energy?
    8·1 answer
  • The ka value for acetic acid, ch3cooh(aq), is 1.8× 10–5. calculate the ph of a 1.60 m acetic acid solution.
    6·1 answer
  • Explain what states are changing in these examples
    14·1 answer
  • Give reason:
    8·1 answer
  • What happens when the compound MgO is formed?
    5·2 answers
  • Analysis of gas produced during combustion determined a compound contained 43.74% C, 3.14% H, 16.61% O A) What is the empirical
    11·1 answer
  • A burning match will burn more vigorously in pure oxygen than in air because _________ . Select one: a. oxygen is a catalyst for
    6·1 answer
  • Why must ionic compound have a total charge of 0?
    9·1 answer
  • Where do plants get their energy?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!