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tatiyna
3 years ago
7

Eight children are divided into an two teams. how many different divisions are possible?

Mathematics
1 answer:
andrew-mc [135]3 years ago
3 0
8C2 =28 C stands for choose hope this helps
You might be interested in
0.48 = log x solve for x
marissa [1.9K]

Answer: x≈3

Step-by-step explanation:

0.48 = log x , this could also be written as :

log_{10} x = 0.48 , that is

x = 10^{0.48}

x = 3.01995172

x≈ 3

8 0
3 years ago
If you know trig please help! Will give brainliest!
kaheart [24]

Answer:

sin^2α

Step-by-step explanation:

I will just  pose  x instead  of alpha  here to make things simpler

\tan ^2\left(x\right)\left(2\cos ^2\left(x\right)+\sin ^2\left(x\right)-1\right)\\\\

we know that sin^2x = 1 -  cos^2x so...

=\left(-1+1-\cos ^2\left(x\right)+2\cos ^2\left(x\right)\right)\tan ^2\left(x\right)

=\cos ^2\left(x\right)\tan ^2\left(x\right)

we can rewrite using trigonometric identities (tan = sin/cos)...

=\left(\frac{\sin \left(x\right)}{\cos \left(x\right)}\right)^2\cos ^2\left(x\right)\\= \sin ^2\left(x\right)

6 0
2 years ago
This is from Khan academy I have to attach a PNG if you can help me solve it! Thank you!
Mekhanik [1.2K]

49^2m-m : Not equivalent

7^2m-2m : Not equivalent

7^2m-m : Not equivalent

This is actually a trick question. All of the following are actually false statements. Want to know why? Let me show you.

For exponents, if you are dividing a number to some power (i.e 5^3) by the SAME number to a different power (i.e 5^2), then the expression is 5^3-2 or 5^1 = 5. This is true for any number a such that a^b ÷ a^c = a^b-c.

Since 7 and 49 are not the same number, this rule does not apply and thus cannot be simplified any further.

Let me prove why. 5^3 = 125, and 5^2 = 25, and 125 ÷ 25 = 5. This is also the same as 5^3-2 = 5^1 = 5. We just proved this as so.

But, what about 7 and 49, or 2 different numbers. Well it doesn't apply. 7^3 = 343, and 49^2 = 2401, and 343 ÷ 2401 ≈ 0.14. Thus, this is NOT equal to 7^3-2 which is 7. We just proved that a^y ÷ b^z ≠ a^y-z. Congratulations!

Hope this helped!

7 0
1 year ago
A set of 4 consecutive odd integers has a sum of 216. What are the integers?​
dezoksy [38]

Answer:

Hope this helps!!

Step-by-step explanation:

So the four consecutive odd integers are: 51 , 53 , 55 and 57 .

If the first integer is n, then the other three are n+2,n+4 and n+6

and we have:

216=n+(n+2)+(n+4)+(n+6)=4n+12

Subtract 12 from both ends and transpose to get:

4n=204

Divide both sides by 4

to get:

n=51

So the four consecutive odd integers are:

51,53, 55 and 57.

8 0
2 years ago
The distance between 2 trees is 11 meters. The first tree is 12 meters and the second tree is 29 meters. What is the distance be
AfilCa [17]

Answer:

In ΔABC

AB  

2

=AC  

2

+BC  

2

 

⇒BC  

2

=x  

2

=17  

2

−8  

2

 ⇒x=15m.

Step-by-step explanation:

8 0
2 years ago
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