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klio [65]
3 years ago
15

I need help please ​

Mathematics
1 answer:
vodka [1.7K]3 years ago
8 0
1) A student will study German for at least 3 years. x≥3
2) All employees work less than 40 hours. x<40
3) There are at least 35 people in the emergency room. x≥35
4) The carton holds at most 12 eggs. x≤12
5) There are no more than 10 gallons of gas in the tanks. x≤10
6) There are fewer than 10 yards of fabric left. x<10
7) The temperature is above 32°F. x>32
8) Years of experience cannot be less than 5 years. x≥5
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Please help ASAP thank you
Zina [86]

Step-by-step explanation:

step 1. 15^18/15^3

step 2. 15^18*15^-3

step 3. 15^(18 - 3)

step 4. 15^15

5 0
2 years ago
I need help i don’t get it
Anastaziya [24]
The answer is 4337 ÷ 9
8 0
3 years ago
Read 2 more answers
What is the best approximation of the solution to the system of the nearest integer values
Natali5045456 [20]

Answer:

  • (2, 3.5) or (2, 3)

Step-by-step explanation:

<em>See attached.</em>

The intersection of the lines is the solution.

<u>Approximate values of the coordinates is:</u>

  • (2, 3.5) or (2, 3) if integer values are required

7 0
2 years ago
Read 2 more answers
I need help on 2 &amp; 3
lora16 [44]

Answer:

NUMBER TWO IS ------ 22,29,37

I DONT KNOW NUMBER THREE

Step-by-step explanation:

I HOPE I HELPED U 229 999 0523

5 0
3 years ago
The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0
3 years ago
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