Yes it helps improve flexibility
Answer: D. Acceleration of Object A is twice of that of the acceleration of Object B.
Answer:
7.35 J
Im assuming, upon answering the question, that the gravity in this scenario is 9.8? As 9.8 is the gravitational force upon the earth.
Answer: A) 0.0394 kg · m2/s
The angular momentum is equal to M = 0.0394kgm^2/s
Explanation:
Given;
Mass of stick = 135g = 0.135kg
Length L = 1m
Angular speed w = 3.50 rad/s
The angular momentum is given as;
M = I×w
Where I = moment of inertia
In this case I is given as;
I = 1/12(m×L^2)
I = 1/12( 0.135 × 1^2)
I = 0.01125kgm^2
The angular momentum can then be calculated as
M = 0.01125kgm^2×3.50rads/s
M = 0.039375kgm^2/s
M = 0.0394kgm^2/s
The angular momentum is equal to M = 0.0394kgm^2/s
Answer:
<621, 0 , 0>
Explanation:
given,
mass of the car ,m = 1425 Kg
location of car = < 266, 0, 0 > m
momentum of the car = < 46000, 0, 0 > kg.m/s
M v_x = 46000
1425 x v_x = 46000
v_x = 32.28 m/s
v_y = 0 m/s
v_z = 0 m/s
Location of the car after 11 s
x = v_x t + 266
x = 32.28 x 11 + 266
x = 621 m
hence, the location of car after 11 s is equal to <621, 0 , 0>