Answer:
a basis or standard for evaluation,assessment or comparison
Explanation:
a point use to find or describe the location of something.
The force required for the car is 5841 N
Explanation:
First of all, we need to find the acceleration of the car, which is given by:
where:
v = 27 m/s is the final velocity of the car
u = 0 is the initial velocity (the car starts from rest)
t = 6 s is the time the car takes to accelerate from u to v
Substituting, we find
Now we can find the force needed to accelerate the car; using Newton's second law of motion,
where:
F is the net force on the car
m = 1298 kg is the mass of the car
is the acceleration
Substituting, we find:
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Answer:
The tension in the cord is 24.1 Newton
Explanation:
<u>Step 1:</u> Data given
mass of the ball = 1.13 kg
Cord = 0.50m
velocity = 2.4 m/s
<u>Step 2:</u> Calculate the tension
Fnet = F(c)
T - F(g) = F(c)
⇒ with F(g) = force of gravity = m*g
⇒ with F(C) = centripetal force = (mv²)/r
T = (mv²)/r + mg
⇒ with m = mass = 1.133 kg
⇒ with v = velocity = 2.4 m/s
⇒ with r = radius = 0.50 m
T = (1.13 * 2.4²) / 0.50 + 1.13 * 9.81
T = 24.1 Newton
The tension in the cord is 24.1 Newton
Answer:
Explanation:
20 km/hr = 5.56 m/s
90 km/hr = 25 m/s
To have just passed C, B must gain first the length of C, then the length of B for a total 400 m
s = s₀ + v₀t + ½at²
if s₀ = 0 at the head of train C when t = 0
for train C, the position in time is
s = 0 + 5.56t + ½(0.2)t²
s = 5.56t + 0.1t²
for train B which must gain 400 m in the same time
s = -400 + 25t + ½(-0.1)t²
s = -400 + 25t - 0.05t²
As both equations equal s, we can set the other sides equal
5.56t + 0.1t² = -400 + 25t - 0.05t²
0.15t² - 19.44t + 400 = 0
quadratic formula positive answer
t = (19.44 + √(19.44² - 4(0.15)(400))) / (2(0.15))
t = 104 s
v = 25 + 104(-0.1) = 14.6 m/s or 52.6 km/hr
Work done = 0.5*m*[(v2)^2 - (v1)^2]
where m is mass,
v2 and v1 are the velocities.
Given that m = 1.50 x 10^3 kg, v2 = -15 m/s (decelerates), v1 = 25 kg,
Work done = 0.5 * 1.50 x 10^3 * ((-15)^2 - 25^2) = 3 x 10^5 joules
Just ignore the negative value for the final result because work is a scalar quantity.