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andriy [413]
3 years ago
10

Ali pushes a toy car initially at rest towards javed by exerting a constant horizontal force F of magnitude 10N through a distan

ce of 2 meters. How much work is done onthe toy car? a 5j b) 10j c) 15j d) 20j e) 25j
Physics
1 answer:
mylen [45]3 years ago
8 0

Answer: d) 20J

Explanation:

Work W done by a Force F refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.  

It should be noted that it is <u>a scalar magnitude</u>, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter:  

1J=(1N)(1m)=Nm  

Now, <u>when the applied force is constant and the direction of the force and the direction of the movement are parallel</u>, the equation to calculate it is:

 

W=(F)(d) (1)

When they are not parallel, both directions form an angle, let's call it \alpha. In that case the expression to calculate the Work is:  

W=Fdcos{\alpha} (2)

In this case both (the force and the distance in the path) are parallel, so the work W performed is the product of the force F by the distance traveled d. as shown in equation (1).

Hence:

W=(10N)(2m)  

W=20Nm=20J >>>>This is the work

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Where could convection currents form? Check all that apply.
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<h3><u>Answer;</u></h3>
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Consider two sizes of disk, both of mass M. One size of disk has radius R; the other has radius 4R. System A consists of two of
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Answer:

4 smaller disks

Explanation:

We are given;

Mass of smaller and larger disks = M

Radius of smaller disk = R

Radius of larger disk = 4R

Formula for moment of inertia about cylinder axis is:

I = ½MR²

Thus;

For small disk, I_small = ½MR²

For large disk, I_large = ½M(2R)² = 2MR²

We are told that moment of inertia of System A consists of two of the larger disks. Thus;

I_A = 2 × I_large = 2 × 2MR²

I_A = 4MR²

We are also told that System B consists of one of the larger disks and a number of the smaller disks. Thus;

I_B = I_large + n(I_small)

Where n is the number of smaller disks.

I_B = 2MR² + n(½MR²)

I_B = MR²(2 + n/2)

We are told that the moment of inertia for system A equals the moment of inertia for system B. Thus;

I_A = I_B

So;

4MR² = MR²(2 + n/2)

MR² will cancel out to give;

4 = 2 + n/2

Multiply through by 2 to give;

8 = 4 + n

n = 8 - 4

n = 4

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Answer:

I will say that the the potential energy will be at its maximum.

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