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3 years ago

11

Part A: Write an algebraic expression for 6 more than 7 times a number. (5 points) Part B: Write a verbal expression for 3(n + 8

). (5 points)

1 answer:

Ymorist [56]3 years ago

8 0

Part a: 7x+6
part b: 3 times the sum of a number and 8
hope this helps!

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Which triangle is a translation of triangle P? On a coordinate plane, triangle P is shifted 5 units to the right and 7 units up

Deffense [45]

Answer:

Triangle C

Step-by-step explanation:

Got it right on edge test

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3 years ago

Help please!! i need this last one to finish!!!! 44 points!!

AleksandrR [38]

Answer:

The point is at about (4.5, 100).

Step-by-step explanation:

Minka's line is p = 22t, which has a y-intercept of 0.

Kenji's line is p = 50 + 11t, which has a y-intercept of 50.

Find the line with y-intercept at 0 and the line with y-intercept at 50. Follow the two lines until they intersect. The point of intersection is about (4.5, 100).

You can find this point by setting the two equations equal to each other:

22t = 50 + 11t

Subtract 11t from both sides.

11t = 50

t = 50/11 ≈ 4.545

Then you can find the p value for this point by plugging t = 4.545 into either equation.

p = 22(4.545) = 99.99

p = 50 + 11(4.545) = 99.995

On the graph the point is about (4.5, 100).

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3 years ago

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3 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

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3 years ago

2^8+6(7-1)+4 does this equal 56

sukhopar [10]

Answer:

nope

Step-by-step explanation:

it acutally equals to 292 I am sure!

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3 years ago