Answer:
C
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are equal, that is
=
, substituting values
=
( cross- multiply )
21x = 7(24 - x) ← distribute
21x = 168 - 7x ( add 7x to both sides )
28x = 168 ( divide both sides by 28 )
x = 6 → C
Answer:
18) 4 * 10 ^ -10
19) t ^ 9
Step-by-step explanation:
18. When multiplying in scientific notation, just multiply the regular numbers together and add the exponents for the tens.
So it'll be 40 * 10^-11
However, the beginning number should have the decimal right after the 4, not any place after (for example, it's 3.056, not 30.56 or 3056.)
To fix this, move the decimal place forward one space from 40. to 4.0, and add 1 to the -11 power.
So the answer is now 4 * 10^-10
19. When dividing exponents, if the base number is the same, you can divide. (Basically, you can not divide x^2 and y^3 because x and y aren't the same)
Since in this case it's t, you can divide.
Dividing exponents is simple: just subtract them.
14 - 5 = 9
so the answer is t ^ 9
Answer:
x = 0 or 
Step-by-step explanation:
We have the quadratic equation of variable x and we have to solve the equation using the square root property.
Now, we have x(3x - 17) = 0
⇒ 3x² - 17x = 0
⇒
⇒
⇒
Now,square rooting both sides we get,
Therefore, either x = 0 or
(Answer)
∠1 and ∠2 are alternate exterior angles where transversal BE crosses parallel lines AC and DF, therefore they are equal. ∠2 and ∠3 are opposite angles of a parallelogram, therefore they are equal.
... ∠1 = ∠2
... 3x -5 = 2x +15 . . . . substitute the given values
... x = 20 . . . . . . . . . . . add 5-2x
The measures of angles 1, 2, and 3 are 2·20+15 = 55 . . . degrees.
As X' is the reflected point of X(0,3) , so the x co ordinate of X' = 0+8 =8 and here y co ordinate remains same.
So, X'= (8,3)
Like that way, Y' is the reflected point of Y(2,0) and Z' is the reflected point of Z(4,2)
As the point Z is lying on the line x=4 and the reflection is also across that line, so both Z and Z' represent same point.
Y'= (2+4, 0) = (6, 0)
Z' = (4, 2)