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cupoosta [38]
3 years ago
11

Help me with this question please

Mathematics
1 answer:
Andrew [12]3 years ago
4 0
<em>Complementary </em>angles are two angles that add up to a <em>right </em>angle, or 90°.

If ∠A and ∠B are complementary, that means that m∠A + m∠B = 90°. Plugging in the given values for m∠A and m∠B, we have

(2x-29) + (x + 23) = 90

Which we can use to solve for x:

2x - 29 + x + 23 = 90
(2x + x) + (-29 + 23) = 90
3x - 6 = 90
3x = 96
x = 32

Since we already know m∠B = (x + 23)°, we can substitute x to find that m∠B = (32 + 23)° = 55°
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Answer:

3 cups of sugar and 6 cups of sugar

PLZ MARK BRAINLIEST!!!

Step-by-step explanation:

6 0
3 years ago
A salmon is swimming in a river that is flowing downstream at a speed of 2 miles per hour. The slamon can swim 12 miles upstream
Olegator [25]

Answer:

The speed of the salmon in still water is 6 mi/h

Step-by-step explanation:

When an object moves with a speed So (So measured in still water) in a river with speed Sr:

If the object moves along the current (downstream), then the actual speed of the object will be:

S = So + Sr

If the object moves upstream, then the velocity will be:

S = So - Sr

In this case we know the speed of the river downstream is 2 mi/h

Sr = 2mi/h

And we know that the salmon can swim 12 miles upstream in the same time (T) that it can swim 24 miles downstream.

Here you need to remember the relation:

Distance = Time*Speed.

Then we know that:

24 mi = (So + 2mi/h)*T

12 mi = (So - 2mi/h)*T

Now we can take the quotient of these two equations to get:

(24mi/12mi) = ( (So + 2mi/h)*T)/((So - 2mi/h)*T)

2 = (So + 2mi/h)/(So - 2mi/h)

Let's multiply both sides by the denominator of the right part:

2*(So - 2mi/h) = (So + 2mi/h)

2*So - 4mi/h = So + 2mi/h

Now we need to isolate So, the speed of the salmon in still water:

2*So - So = 2mi/h + 4mi/h

So = 6mi/h

The speed of the salmon in still water is 6 mi/h

7 0
3 years ago
Paul ran a 26 1/5 mile marathon in 2 3/4 hours. Write an inequality to describe the average speeds s of runners who were faster
Scilla [17]

Answer:

  • s > 9 29/55

Step-by-step explanation:

Paul ran a 26 1/5 mile marathon in 2 3/4 hours

<u>Paul's average speed was:</u>

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  • 131/5 * 4/11 =
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<u>Inequality for the speed of faster runners:</u>

  • s > 9 29/55
6 0
3 years ago
What is the value of the expression?
Anni [7]
The answer is d) that is the answer.

5 0
3 years ago
Which of these graphs represents a function ?
ddd [48]

Answer:

Graph C

Step-by-step explanation:

6 0
3 years ago
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