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Oksanka [162]
4 years ago
14

Mr. and Mrs. Delgado each own an equal number of shares of a stock.Mr. Delgado sells one-third of his shares for $2700. What was

the value of Mr. and Mrs.Gelgados stock before the sale?
Mathematics
1 answer:
liubo4ka [24]4 years ago
7 0
3x2700=Just Mr. Delgado's shares' value= $8100

Since they own an equal number of shares, their total value of stock before the sale is two times what each of them has separately.

$8100 x 2=value of their stock= $16200
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My state's lottery has 30 white balls numbered from 1 through 30 and 20 red balls numbered from 1 through 20. In each lottery dr
seropon [69]

The three whites:

(30 choose 1) * (29 choose 1) * (28 choose 1) = 30 * 29 * 28


The two reds:

(20 choose 1) * (19 choose 1) = 20 * 19


So, The three whites + two reds = 30 * 29 * 28 + 20 * 19 = 24740

7 0
3 years ago
The volume of this triangular prism is 32 cubic inches. What is the value of d?
krek1111 [17]

Answer:

Divide the volume by the length of the prism to get the area of the face:

468/13 = 36 square yards.

The area of the face ( triangle) is 1/2 x base x height

Replace with what you have:

36 = 1/2 x 9 x g

Multiply both sides by 2 to remove the 1/2:

72 = 9 x g

Divide both sides by 9 to find g:

g = 72 /9

g = 8 yards.

3 0
3 years ago
Number 9 help, please
Drupady [299]

Answer:

Unique

Step-by-step explanation:

5 0
3 years ago
??????????????????????
Leviafan [203]
√(x + 9) - 4 = 1
√(x + 9) - 4 (+4) = 1 (+4)
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6 0
4 years ago
A Web ad can be designed from four different colors, three font types, five font sizes, three images, and five text phrases. A s
Varvara68 [4.7K]

Answer:

P(A∪B)=17/20 or 0.85

P(A∪B')=2/5 or 0.4

P(A'∪B')=4/5 or 0.8

Step-by-step explanation:

There are four font colors so each color had equal chance and thus,

P(A)=1/4

There are 5 font sizes and so not the smallest fonts are 4.Thus,

P(B)=4/5

P(A∪B)=P(A)+P(B)-P(A∩B)

The design is generated randomly so event A and event B are independent.

P(A∩B)=P(A)*P(B)

P(A∩B)=1/4(4/5)=1/5

P(A∪B)=P(A)+P(B)-P(A∩B)

P(A∪B)=1/4+4/5-1/5=1/4+3/5

P(A∪B)=17/20 or 0.85

P(A∪B')=P(A)+P(B')-P(A∩B')

P(B')=1-P(B)=1-4/5=1/5

P(A∩B')=P(A)*P(B')=1/4*1/5=1/20

P(A∪B')=P(A)+P(B')-P(A∩B')

P(A∪B')=1/4+1/5-1/20=9/20-1/20=8/20

P(A∪B')=2/5 or 0.4

P(A'∪B')=P(A∩B)'

P(A'∪B')=1-P(A∩B)

P(A'∪B')=1-1/5=4/5

P(A'∪B')=4/5 or 0.8

5 0
3 years ago
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