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borishaifa [10]
3 years ago
11

A chimical reaction is supposed to produce 1.44 g of product X. When the reaction is carried out, only 1.31 g of product X are f

ormed. What is the percenr error in the yield of the reaction?
Chemistry
1 answer:
Vera_Pavlovna [14]3 years ago
8 0
[percent] {error} = abs ( \frac{#experemental - theoretical}{theoretical}) *100=






==abs( \frac{1.31-1.44}{1.44} )*100 = 9.03

Answer is 9.03%.
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no because the suns light is way more bright than lightbulbs.

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Equation for the reaction btn nitric acid and metal X whose valence is 3​
viva [34]
(a) Reaction of nitric acid with non-metal:
C+4HNO
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(b) Nitric acid showing acidic character:
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hope that helps you please mark brainliest
3 0
2 years ago
What is the percentage of hydrogen in c2h4
jarptica [38.1K]

Ethylene- C2H4 = 85.7% Carbon and 14.3% Hydrogen


Find the atomic masses for each element and multiply it by the number of atoms in the compound, then add.


C- 12.0 * 2= 24.0


H- 1.00 * 4= 4.00


-----------------------


28.0


Take the masses for each element and divide it by the total mass. Then change the answer to get the percent.


C 24.0 / 28.0= .857 = 85.7%


H 4.00 / 28.0= .143 = 14.3%


<h3>Ethylene is 85.7% Carbon and 14.3% Hydrogen </h3>
8 0
3 years ago
When you place a glass over a candle and the flame goes out, the limiting reactant is, oxygen wax energy water ​
jeka57 [31]

Answer: oxygen

Explanation:

4 0
3 years ago
Calculate the number of moles of O2 gas held in a sealed 2.00 L tank at 3.50 atm and 25 ℃.
Leviafan [203]

Answer:

n=0.286mol

Explanation:

Hello,

In this case, we consider oxygen as an ideal gas, for that reason, we use yhe ideal gas equation to compute the moles based on:

PV=nRT\\\\n=\frac{PV}{RT}

Hence, at 3.50 atm and 25 °C for a volume of 2.00 L we compute the moles considering absolute temperature in Kelvins:

n=\frac{3.50atm*2.00L}{0.082\frac{atm*L}{mol*K}(25+273)K} \\\\n=0.286mol

Best regards.

6 0
3 years ago
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