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borishaifa [10]
3 years ago
11

A chimical reaction is supposed to produce 1.44 g of product X. When the reaction is carried out, only 1.31 g of product X are f

ormed. What is the percenr error in the yield of the reaction?
Chemistry
1 answer:
Vera_Pavlovna [14]3 years ago
8 0
[percent] {error} = abs ( \frac{#experemental - theoretical}{theoretical}) *100=






==abs( \frac{1.31-1.44}{1.44} )*100 = 9.03

Answer is 9.03%.
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Hibernation is _______. A. An example of an abiotic cycle b. Triggered by changes in the weather c. Caused only by biotic factor
natta225 [31]

The correct answer is option b, that is, triggered by changes in the weather.  

Hibernation refers to a state of lower metabolism and inactivity usually witnessed in endotherms. This condition is featured by a slow heart rate, slow breathing, low metabolic rate, and low body temperature. It assists the majority of the endotherms to thrive in the cold seasons. For example, hibernation of a bear in winters. Therefore, weather change can stimulate hibernation.  


6 0
4 years ago
We have two surfaces A and B where same amount of Force is acting. Area of Surface A is greater than Area of Surface B. which of
Phoenix [80]

Answer:

Pressure on Surface A > Pressure on Surface B

Explanation:

Pressu

re on Surface B > Pressure on Surface A

7 0
3 years ago
Is calcium carbonate a compound element or mixture?
uysha [10]

It's a compound because it's formed from an ionic bond between calcium and carbon so it's an ionic compound

7 0
4 years ago
Telluric acid (H2TeH4O6) is a diprotic acid with Ka1 = 2.0x10-8 and Ka2 = 1.0x10-11. A 0.25 M H2TeH4O6 contains enough HCl so th
tensa zangetsu [6.8K]

Answer:

5x10⁻⁶ = [HTeH₄O₆⁺]

Explanation:

The first dissociation equilibrium of the telluric acid in water is:

H₂TeH₄O₆ + H₂O ⇄ HTeH₄O₆⁺ + H₃O⁺

Using H-H equation for telluric acid:

<em>pH = pKa + log₁₀ [HTeH₄O₆⁺] / [H₂TeH₄O₆]</em>

pKa of telluric acid is -logKa1

pKa = -log 2.0x10⁻⁸

pKa = 7.699

As concentration of [H₂TeH₄O₆] is 0.25M, replacing in H-H equation:

3.00 = 7.699+ log₁₀ [HTeH₄O₆⁺] / [0.25M]

-4.699 = log₁₀ [HTeH₄O₆⁺] / [0.25M]

2x10⁻⁵ = [HTeH₄O₆⁺] / [0.25M]

<h3>5x10⁻⁶ = [HTeH₄O₆⁺]</h3>

7 0
3 years ago
Cu(OH)₂ +H₃PO₄ = Cu₃(PO₄)₂+H₂O<br><br> how do i balance this equation
swat32

balanced equation =

3Cu(OH)2 + 2H3PO4 → Cu3(PO4)2 + 6H2O

3 0
2 years ago
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