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Brut [27]
3 years ago
8

Wasim and his friends want to test if the solution of a substance is acidic or not. These are the tests that each of them perfor

med. Wasim: Dipped the blue litmus in the solution Akram: Dipped the red litmus in the solution Neha: Dipped both the blue and the red litmus in the solution one after other. Who among them performed a proper test ?
Chemistry
1 answer:
alex41 [277]3 years ago
3 0

Answer:

Wasim and Nehra did the Proper testing  

Explanation:

In acidic condition Blue litmus turns red

In basic condition Red litmus turns Blue

In order to test an Acidic solution we need Blue litmus.

Wasim Dipped the blue litmus in the solution : it will turn red and shows acid

Akram  Dipped the red litmus in the solution : No it will not show, it's a test for base

Neha: Dipped both the blue and the red litmus in the solution one after other.

          Blue litmus will turn red which will show Acidic nature, after that Adding Red litmus in it will not show any change as Red litmus only changes in Basic condition.

Therefore,  Wasim and Nehra did the Proper  testing  

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What should be the temperature of the solvent before adding it to the sample to be recrystallized?
Serhud [2]

Answer:

Near the boiling point of the solvent

Explanation:

The process of recrystallization is hinged on the fact that the amount of solute that can be dissolved by a solvent increases with temperature. The process involves creation of a solution by dissolving a solute in a solvent at or near its boiling point.  At the boiling point of the solvent, the solute has a greater solubility in the solvent; not much volume of  the hot solvent is required to dissolve the solute.

Before the solution is later cooled, you can now filter out insoluble impurities from the hot solvent. The quantity of the original solute drops appreciably because impurities have been removed. At this lower temperature, the solution becomes saturated and the solute can no longer be held in solution hence it forms pure crystals of solute, which can be recovered.

Recrystallization must be carried out using the proper solvent. The solute must be relatively insoluble in the solvent at room temperature but more soluble in the solvent at elevated temperature.

3 0
3 years ago
How does Arizona's climate relate to the air and ocean currents?
harkovskaia [24]

Answer: In Arizona, climate change is already making deadly heat waves, droughts and wildfires across the state worse. These impacts have real costs on Arizonans' health and economy, including heat-related deaths, higher electricity bills, crop losses and more.

Explanation:

https://www.edf.org/climate/costofinaction- this is where I gathered this info.  Not mine.  But I hope it helps!

6 0
3 years ago
A sample of gas is observed to effuse through a pourous barrier in 4.98 minutes. Under the same conditions, the same number of m
kogti [31]

Answer:

The molar mass of the unknown gas is \mathbf{ 51.865 \  g/mol}

Explanation:

Let assume that  the gas is  O2 gas

O2 gas is to effuse through a porous barrier in time t₁ = 4.98 minutes.

Under the same conditions;

the same number of moles of an unknown gas requires  time t₂  =  6.34 minutes to effuse through the same barrier.

From Graham's Law of Diffusion;

Graham's Law of Diffusion states that, at a constant temperature and pressure; the rate of diffusion of a gas is inversely proportional to the square root of its density.

i.e

R \  \alpha  \ \dfrac{1}{\sqrt{d}}

R = \dfrac{k}{d}  where K = constant

If we compare the rate o diffusion of two gases;

\dfrac{R_1}{R_2}= {\sqrt{\dfrac{d_2}{d_1}}

Since the density of a gas d is proportional to its relative molecular mass M. Then;

\dfrac{R_1}{R_2}= {\sqrt{\dfrac{M_2}{M_1}}

Rate is the reciprocal of time ; i.e

R = \dfrac{1}{t}

Thus; replacing the value of R into the above previous equation;we have:

\dfrac{R_1}{R_2}={\dfrac{t_2}{t_1}}

We can equally say:

{\dfrac{t_2}{t_1}}=  {\sqrt{\dfrac{M_2}{M_1}}

{\dfrac{6.34}{4.98}}=  {\sqrt{\dfrac{M_2}{32}}

M_2 = 32 \times ( \dfrac{6.34}{4.98})^2

M_2 = 32 \times ( 1.273092369)^2

M_2 = 32 \times 1.62076418

\mathbf{M_2 = 51.865 \  g/mol}

7 0
3 years ago
Of the following transitions in the Bohr hydrogen atom, the ________ transition results in the emission of the lowest-energy pho
Sladkaya [172]
N=6 ——> n=1
hope this helps!
5 0
3 years ago
Determine whether or not each mixture is a buffer. check all that apply. check all that apply. hcl and hf hf and naf hc2h3o2 and
maksim [4K]
Hello!

A buffer is composed of a weak acid and its conjugate base or a weak base and its conjugate acid. From the given list:

HCl and HF: Strong Acid and Weak Acid. NOT BUFFER

HF and NaF: Weak Acid and Conjugate Base. BUFFER

HC₂H₃O₂ and  KC₂H₃O₂: Weak Acid and Conjugate Base. BUFFER

NaOH and NH₃: Strong Base and Weak Base. NOT BUFFER.

Have a nice day!
7 0
3 years ago
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