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Brut [27]
3 years ago
8

Wasim and his friends want to test if the solution of a substance is acidic or not. These are the tests that each of them perfor

med. Wasim: Dipped the blue litmus in the solution Akram: Dipped the red litmus in the solution Neha: Dipped both the blue and the red litmus in the solution one after other. Who among them performed a proper test ?
Chemistry
1 answer:
alex41 [277]3 years ago
3 0

Answer:

Wasim and Nehra did the Proper testing  

Explanation:

In acidic condition Blue litmus turns red

In basic condition Red litmus turns Blue

In order to test an Acidic solution we need Blue litmus.

Wasim Dipped the blue litmus in the solution : it will turn red and shows acid

Akram  Dipped the red litmus in the solution : No it will not show, it's a test for base

Neha: Dipped both the blue and the red litmus in the solution one after other.

          Blue litmus will turn red which will show Acidic nature, after that Adding Red litmus in it will not show any change as Red litmus only changes in Basic condition.

Therefore,  Wasim and Nehra did the Proper  testing  

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Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
4 years ago
5. A gas occupies a volume of 100.0 mL at 27.0°C and 630.0 torr. At what temperature, in degrees
DanielleElmas [232]

100 by 500 ml so if you put 50 ml in 630torr it would evaporate

Explanation:

it is more than ¹00 celcwius so it would eveporate

8 0
3 years ago
In the titration of HCl with NaOH, the equivalence point is determined
kondaur [170]

Answer:

In the titration of HCl with NaOH, the equivalence point is determined from the point where the phenolphthalein turns pink and then remains pink on swirling.

Explanation:

The equivalence point is the point at which exactly enough titrant (NaOH) has been added to react with all of the analyte (HCl). Up to the equivalence point, the solution will be acidic because excess HCl remains in the flask.

Phenolphtalein is chosen because it changes color in a pH range between 8.3 – 10. Phenolphthalein is naturally colorless but turns pink in alkaline solutions. It remains colorless throughout the range of acidic pH levels, but it begins to turn pink at a pH level of 8.3 and continues to a bright purple in stronger alkalines.

It will appear pink in basic solutions and clear in acidic solutions.

The more NaOH added, the more pink it will be. (Until pH≈ 10)

In strongly basic solutions, phenolphthalein is converted to its In(OH)3− form, and its pink color undergoes a rather slow fading reaction and becomes completely colorless above 13.0 pH

a. from the point where the pink phenolphthalein turns colorless and then remains colorless on swirling.

⇒ the more colorless it turns, the more acid the solution. (More HCl than NaOH)

b. from the point where the phenolphthalein turns pink and then remains pink on swirling.

The equivalence point is the point where phenolphtalein turns pink and remains pink ( Between ph 8.3 and 10). (

Although, when there is hydrogen ions are in excess, the solution remains colorless. This begins slowely after ph= 10 and can be noticed around ph = 12-13

c. from the point where the pink phenolphthalein first turns colorless and then the pink reappears on swirling.

Phenolphthalein is colorless in acid solutions (HCl), and will only turn pink when adding a base like NaOH

d. from the point where the colorless phenolphthalein first turns pink and then disappears on swirling

Phenolphthalein is colorless in acid or neutral solutions. Once adding NaOH, the solution will turn pink. The point where the solution turns pink, and stays pink after swirling is called the equivalence point. When the pink color disappears on swirling, it means it's close to the equivalence point but not yet.

3 0
3 years ago
If you lived in Alaska, which of the following natural gases could you keep in an outdoor storage tank in winter: a. Methane (CH
wariber [46]

Answer:

Methane

Explanation:

The gas that you could keep in an outdoor storage tank in winter in Alaska is Methane.

The reason is the extreme low temperature during the winter. The boiling point of butane is 44 ºF ( -1ºC) and that of propane is a higher -43.6 º F but still within the range of average minimum winter temperature in Alaska (-50 ªF). Therefore we will have condensation in the tanks and not enough gas pressure.

Methane having  a boling point  of  -259 ºF will not condense at the low wintertime temperatures in Alaska.

3 0
3 years ago
Read 2 more answers
How Many Significant Figures are there in 505
cupoosta [38]

Answer:

there are three significant digits.

Explanation:

Thus,  21.8, 0.283 and 567 all have three significant digits. 2. Zeros appearing between non-zero digits are significant. Thus, 505 and 0.206 have three significant digits, while 50,005 has five significant digits.   (from google)

7 0
3 years ago
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