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Marianna [84]
3 years ago
6

What volume would 3.01•1023 molecules of oxygen gas occupy at STP?

Chemistry
1 answer:
Sliva [168]3 years ago
6 0
First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2


Second, multiply moles by the standard molar volume of a gas at STP:(0.5mol)(22.4L) = 11.2L O2
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