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Marianna [84]
3 years ago
6

What volume would 3.01•1023 molecules of oxygen gas occupy at STP?

Chemistry
1 answer:
Sliva [168]3 years ago
6 0
First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2


Second, multiply moles by the standard molar volume of a gas at STP:(0.5mol)(22.4L) = 11.2L O2
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Consider a cobalt-silver voltaic cell that is constructed such that one half-cell consists of the cobalt, Co, electrode immersed
umka21 [38]

Answer:

Anode half reaction;

Co(s) ----> Co^2+(aq) + 2e

Cathode half reaction;

2Ag^+(aq) + 2e-------> 2Ag(s)

Explanation:

A voltaic cell is an electrochemical cell that spontaneously produces electrical energy from chemical reactions. A voltaic cell comprises of an anode (where oxidation occurs) and a cathode (where reduction occurs). The both electrodes are connected with a wire . A salt bridge ensures charge neutrality in the anode and cathode compartments. Electrons flow from anode to cathode.

For the cell referred to in the question;

Anode half reaction;

Co(s) ----> Co^2+(aq) + 2e

Cathode half reaction;

2Ag^+(aq) + 2e-------> 2Ag(s)

3 0
3 years ago
15.True or False:
Nadusha1986 [10]
True
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3 0
3 years ago
What is -22 = -9+ n​
Anestetic [448]

Answer:

n= -13

Explanation:

-22 = -9 + n

first flip the equation

n + -9 = -22

then add 9 beacuse we need to do the opposite to find n

so -22 + -9 = - 13

so n = -13

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8 0
3 years ago
A balloon has a volume of 3.50 liters at 20.0°C. What will be the volume of the balloon at 100.0°C? Assume the pressure doesn't
Nikitich [7]

<u>Answer:</u> The volume of balloon at 100°C is 4.46 L

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=3.50L\\T_1=20^oC=(20+273)K=293K\\V_2=?L\\T_2=100^oC=(100+273)K=373K

Putting values in above equation, we get:

\frac{3.5L}{293K}=\frac{V_2}{373K}\\\\V_2=4.46L

Hence, the volume of balloon at 100°C is 4.46 L

5 0
3 years ago
How many milliliters of .75 M hydrochloric acid (HCl) are required to neutralize 60.0 ml of .3 M potassium hydroxide (KOH)?
Anvisha [2.4K]

Answer:

24 millilitres

Explanation:

The reaction between hydrochloric acid (HCl) and potassium hydroxide (KOH) is as following:

HCl + KOH => KCl + H2O

Here, Molarity of KOH = 0.3 M per liter

1L = 1000ml

60ml = 0.06 L

moles of KOH = 0.3 x 0.060  L = 0.018 mol (Normalize the volumes)

Molarity of HCL = 0.75 M per liter

Therefore, volume of HCl =  \frac{0.018}{0.75} = 0.024 L

Hence, volume of HCl = 24 millilitres

6 0
3 years ago
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