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Marianna [84]
4 years ago
6

What volume would 3.01•1023 molecules of oxygen gas occupy at STP?

Chemistry
1 answer:
Sliva [168]4 years ago
6 0
First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2


Second, multiply moles by the standard molar volume of a gas at STP:(0.5mol)(22.4L) = 11.2L O2
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Which type of stoichiometric calculation does not require the use of the molar mass?
Marianna [84]
The choices can be found elsewhere and as follows:

a. mass-mass problems 
<span>b. mass-volume problems </span>
<span>c. mass-particle problems </span>
<span>d. volume-volume problems
</span>
I believe the correct answer is option D. It is volume-volume problems that does not require the use of molar mass. <span> Here you are dealing with molarities and volumes to determine concentrations. Molar mass is not part of any calculations.</span>
6 0
3 years ago
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Answer:

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false

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They slow down the air but speed up the water.

pt:2

answering the pictures

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Explanation:

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3 0
3 years ago
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3 years ago
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Vaselesa [24]

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Ann [662]

It is not equal because it dose not obey the conservation of mass. 60+25= 85 not 75.

4 0
4 years ago
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