Question

A car with an initial velocity of O m/s and a mass of 1500 kg reaches a velocity of 15 m/s in 5

Answer 1

The acceleration of the car is $3 m / s^{2}$. And the force required to reach the acceleration is 4500 N.

Explanation:

Equations of Motion describe different relations between motion parameters. One of them is,

                    $v_{f}=v_{i}+a t$

And, $F=m \times a$ , from Newton’s laws

So, given,

Initial velocity of the car $v_{i}$ = 0  

Mass of the car, m = 1500 kg

Velocity acquired $v_{f}$ = 15 m/s

Time taken to acquire velocity t = 5 seconds.

Now, since  $v_{f}=v_{i}+a t$, To find the acceleration, rearrange the above equation, we get as follows,

               $a=\frac{\left(v_{f}-v_{i}\right)}{t}$

Then, by applying the given data in above equation, we get

                $a=\frac{(15-0)}{5}=\frac{15}{5}=3 m / s^{2}$

Now, find the force to reach $3 m / s^{2}$ acceleration as follows,

                $F=m \times a=1500 \times 3=4500 N$

Answer 2

Answer:the answer can be find out by the following steps;

Explanation: