All categories

3 years ago

A car with an initial velocity of O m/s and a mass of 1500 kg reaches a velocity of 15 m/s in 5

Physics

2 answers:

umka21 [38]3 years ago

6 0

The acceleration of the car is $3 m / s^{2}$ . And the force required to reach the acceleration is 4500 N.

<u>Explanation:</u>

Equations of Motion describe different relations between motion parameters. One of them is,

$v_{f}=v_{i}+a t$

And, $F=m \times a$ , from Newton’s laws

So, given,

Initial velocity of the car $v_{i}$ = 0

Mass of the car, m = 1500 kg

Velocity acquired $v_{f}$ = 15 m/s

Time taken to acquire velocity t = 5 seconds.

Now, since $v_{f}=v_{i}+a t$ , To find the acceleration, rearrange the above equation, we get as follows,

$a=\frac{\left(v_{f}-v_{i}\right)}{t}$

Then, by applying the given data in above equation, we get

$a=\frac{(15-0)}{5}=\frac{15}{5}=3 m / s^{2}$

Now, find the force to reach $3 m / s^{2}$ acceleration as follows,

$F=m \times a=1500 \times 3=4500 N$

Flura [38]3 years ago

3 0

Answer:the answer can be find out by the following steps;

Explanation:

You might be interested in

In midair an M = 145 kg bomb explodes into two pieces of m1 = 115 kg and another, respectively. Before the explosion, the bomb w

Daniel [21]

Answer:

$v_2=-133.17m/s$ , the minus meaning west.

Explanation:

We know that linear momentum must be conserved, so it will be the same before ( $p_i$ ) and after ( $p_f$ ) the explosion. We will take the east direction as positive.

Before the explosion we have $p_i=m_iv_i=Mv_i$ .

After the explosion we have pieces 1 and 2, so $p_f=m_1v_1+m_2v_2$ .

These equations must be vectorial but since we look at the instants before and after the explosions and the bomb fragments in only 2 pieces the problem can be simplified in one dimension with direction east-west.

Since we know momentum must be conserved we have:

$Mv_i=m_1v_1+m_2v_2$

Which means (since we want $v_2$ and $M=m_1+m_2$ ):

$v_2=\frac{Mv_i-m_1v_1}{m_2}=\frac{Mv_i-m_1v_1}{M-m_1}$

So for our values we have:

$v_2=\frac{(145kg)(24m/s)-(115kg)(65m/s)}{(145kg-115kg)}=-133.17m/s$

5 0

3 years ago

PLEASE HELP ANSWER FAST As the vibration of molecules decreases, the _____ of the substance decreases. 1.temperature 2.internal

Aleksandr [31]

I think 1 and 3 is absolutely right but im not sure about number 2.
I think the answer is 4 all of the above because as the vibration decrease automatically the kinetic energy decrease and the temperature is decrease because when the vibration of molecules decrease thats mean the substances is slightly become a solid and you can get a solid cube of liquid if you freeze them

8 0

2 years ago

When you jump from an elevated position you usually bend your knees upon reaching the ground. By doing this, you make the time o

dsp73

Answer:

c. about 1/10 as great.

Explanation:

While jumping form a certain height when we bend our knees upon reaching the ground such that the time taken to come to complete rest is increased by 10 times then the impact force gets reduced to one-tenth of the initial value when we would not do so.

This is in accordance with the Newton's second law of motion which states that the rate of change in velocity is directly proportional to the force applied on the body.

Mathematically:

$F\propto\frac{d}{dt} (p)$