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The two smallest major planets, Mercury and Mars, are both smaller than the estimated size of the Earth's core (combined inner and outer core). Mercury has a diameter of about 4879 km and Mars is about 6792 km, compared to the Earth's core which is a sphere about 6972 km in diameter. All of the dwarf planets (Pluto, Eris, Haumea, Makemake, and Ceres) are smaller in diameter than even the Earth's solid inner core (~2440 km in diameter), although Eris is almost as large and Pluto only slightly smaller than Eris. -The Earth's inner core has a thickness (radius) of about 1220 km. -The Earth's outer core has a thickness (radius) of about 2266 km.
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Answer:
The amount of P₄S₃ produced is 0.16 moles.
Explanation:
The balanced reaction is:
8 P₄ + 3 S₈ → 8 P₄S₃
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate:
- P₄: 8 moles
- S₈: 3 moles
- P₄S₃: 8 moles
Being the molar mass of each compound:
- P₄: 123.895 g/mol
- S₈: 256 g/mol
- P₄S₃: 220.093 g/mol
then by stoichiometry of the reaction, the following amounts of reactant and product participate in the reaction:
- P₄: 8 moles* 123.895 g/mol= 991.16 g
- S₈: 3 moles* 256 g/mol= 768 g
- P₄S₃: 8 moles* 220.093 g/mol= 1,760.744 g
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
In this case, you calculate the limiting reactant using the following rule of three: if by stoichiometry 768 g of S₈ react with 991.16 g of P₄, 40 g of S₈ with how much mass of P₄ will it react?
mass of P₄= 51.62 grams
But 51.62 grams of P₄ are not available, 20 grams are available. Since you have less mass than you need to react with 40 grams of S₈, P₄ will be the limiting reagent.
Then you can apply the following rule of three: if by stoichiometry 991.16 grams of P₄ form 8 moles of P₄S₃, 20 grams of P₄ will form how many moles of P₄S₃?
moles of P₄S₃= 0.16
<u><em>The amount of P₄S₃ produced is 0.16 moles.</em></u>
Answer:
2.12×10²³ atoms.
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms. This simply means that 1 mole of zirconium also 6.02×10²³ atoms.
Thus, we can obtain the number of atoms present in 0.3521 mole of zirconium as follow:
1 mole of zirconium also 6.02×10²³ atoms.
Therefore, 0.3521 mole of zirconium will contain = 0.3521 × 6.02×10²³ = 2.12×10²³ atoms.
Therefore, 0.3521 mole of zirconium contains 2.12×10²³ atoms.