Answer: 0.4mL of the stock solution is needed
Explanation:
This is simply a dilution analysis. From the question, the following were obtained:
C1 = 25 mg/mL = 25x10^-3g/mL
V1 =?
C2 = 25 ug/mL = 25x10^-6g/mL
V2 = 400ml
Applying the dilution formula, we have:
C1V1 = C2V2
25x10^-3 x V1 = 25x10^-6 x 400
Divide both side by 25x10^-3, we have:
V1 = (25x10^-6 x 400) / 25x10^-3
V1 = 0.4mL
Therefore, 0.4mL of the stock solution need.
0.53 x 200ml = 106 ml of the pH 9.0 buffer + 94 ml of the pH 10 buffer gives the desired solution
<span> </span>
Answer:
HCl is the limiting reactant.
Explanation:
The reactant that yields the lesser number of moles of product is the limiting reactant
Number of moles of MnO2= mass of MnO2/ molar mass of MnO2
Number of moles= 37.7g/86.9368 g/mol= 0.4336 moles
From the reaction equation,
If 1 mole of MnO2 yields 1 mole of chlorine gas
0.4336 moles of MnO2 also yield 0.4336 moles of chlorine gas
For HCl
Number of moles of HCl= mass of HCl/ molar mass of HCl
Number of moles= 46.3g/36.46 g/mol = 1.27 moles of HCl
If 4 moles of HCl yields 1 mole of chlorine gas
1.27 moles of HCl will yield 1.27×1/4 = 0.3175 moles of HCl
Hence HCl is the limiting reactant.
Answer:
B. n-octyl alcohol and 1-octene
Explanation:
Thin-layer chromatography (TLC) is a chromatography technique used to separate non-volatile mixtures. The principle is that different compounds in the sample mixture travel at different rates due to the differences in interactions with stationary phase and due to the differences in solubility in the solvent. The principal chemical property for separation using this technique is molecular polarity
You can intuit than hexadecane and octadecane don't have big polarity differences, also chlorobenzene and bromobenzene haven't.
An alcohol as n-octyl alcohol has different polarity than an alkene as 1-octene.
Thus, using thin layer chromatography is most easy to separate:
<em>B. n-octyl alcohol and 1-octene
</em>
<em></em>
I hope it helps!
<em></em>
