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Helen [10]
3 years ago
11

At 60°c, the ion-product constant of water, kw, is 9.25 × 10–14 . what is the ph of pure water at 60°c ?

Chemistry
1 answer:
Rus_ich [418]3 years ago
3 0

Answer:

6.517.

Explanation:

  • It is known that for pure water: [H₃O⁺] = [OH⁻], so water is neutral.  

  • It also is known that:

<em>Kw = [H₃O⁺][OH⁻] = 9.25 x 10⁻¹⁴.</em>

∵ [H₃O⁺] = [OH⁻].

∴ [H₃O⁺]² = 9.25 x 10⁻¹⁴.

∴ [H₃O⁺] = √(9.25 x 10⁻¹⁴) = 3.041 x 10⁻⁷ M.

∵ pH = - log[H₃O⁺]

<em>∴ pH</em> = - log(3.041 x 10⁻⁷) = <em>6.517.</em>

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Answer:

\huge\boxed{\sf 36\ H\ atoms}

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\rule[225]{225}{2}

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