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salantis [7]
3 years ago
15

Calculate the [H3O+] of an aqueous solution that is 2.42 × 10−7 M in OH−.

Chemistry
1 answer:
kompoz [17]3 years ago
4 0

Answer:

The (H30+) is 4,13x10-8

Explanation:

We use the formula

Kwater = (H30 +) x (OH-)

1.00e-14 = (H30 +) x 2.42e-7

(H30 +) = 1.00e-14 / 2.42e-7 = 4.13e-8M

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The solution for this problem is:
C6H5NH3Cl is a strong salt: C6H5NH3+ + Cl- C6H5NH3+ + H2O <-----> C6H5NH2 + H3O+ 
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