When there is an electric force acting on an object, the direction in which an object may accelerate has to do with
1 answer:
You might be interested in
Answer:
hello your question lacks some data and required diagram
G = 77 GPa, т all = 80 MPa
answer : required diameter = 252.65 * 10-^3 m
Explanation:
Given data :
force ( P ) = 660 -N force
displacement = 15 mm
G = 77 GPa
т all = 80 MPa
i) Determine the required diameter of shaft BC
considering the vertical displacement ( looking at handle DC from free body diagram )
D' = 0.3 sin∅ , where D = 0.015
hence ∅ = 2.8659°
calculate the torque acting at angle ∅ of CD on the shaft BC
Torque = 660 * 0.3 cos∅
= 660 * 0.3 * cos 2.8659 = 198 * -0.9622 = 190.5156 N
hello attached is the remaining part of the solution
Complete Question
The complete question is shown on the first uploaded image
Answer:
The acceleration would be
Explanation:
The objective of this solution is to obtain the acceleration of the particle
Now looking at Newton law which is mathematically represented as
Where F is the force experience by a particle
m is the mass of the particle
a is the acceleration of the particle
And also this force is equivalent to magnetic force in a magnetic field which is mathematically represented as
Where q is the charge of the particle
v is the velocity of the charge
B is the magnetic field the charge is under it influence
Now equating this two formulas
Making a the subject we have
In the question the direction of the is in the positive x-axis which is hence the direction would be in the
direction
So substituting for B
Substituting for v and
for q
According to vector multiplication
So
