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Naya [18.7K]
3 years ago
12

What results electrons into having light produced by neon gas?

Chemistry
1 answer:
maxonik [38]3 years ago
4 0
The answer on Google is more in detail but basically the electrons flow and create this energy for the lights to work
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Can someone please help me?
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Answer:the mass of the gases and ash should be equal the mass of the initial stack of newspapers, there are equal number of atoms on both sides

Explanation:no matter what form the newspaper would take the mass stays the same because all you did is burn it, conserve means that each atom's mass will stay the same no matter what.

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Look at the diagram. Which shows the correct arrangement of electrons in a hydrogen molecule?
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When a mineral was heated in a Bunsen flame to constant mass, a colourless gas that turned lime water milky was evolved. The rem
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The amount of matter in a given space or volume
ivolga24 [154]

Answer:

i'm not sure but i think

Explanation:

matter Anything that has mass and occupies space.

density The amount of matter in a given volume of space.

formula for density mass divided by volume

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I hope it helps

5 0
3 years ago
Read 2 more answers
For a particular reaction at 235.8 °C, ΔG=−936.92 kJ/mol , and ΔS=513.79 J/(mol⋅K) . Calculate ΔG for this reaction at −9.9 °C.
Rudik [331]

Answer:

-138.9 kJ/mol

Explanation:

Step 1: Convert 235.8°C to the Kelvin scale

We will use the following expression.

K = °C + 273.15 = 235.8°C + 273.15 = 509.0 K

Step 2: Calculate the standard enthalpy of reaction (ΔH°)

We will use the following expression.

ΔG° = ΔH° - T.ΔS°

ΔH° = ΔG° / T.ΔS°

ΔH° = (-936.92kJ/mol) / 509.0K × 0.51379 kJ/mol.K

ΔH° = -3.583 kJ (for 1 mole of balanced reaction)

Step 3: Convert -9.9°C to the Kelvin scale

K = °C + 273.15 = -9.9°C + 273.15 = 263.3 K

Step 4: Calculate ΔG° at 263.3 K

ΔG° = ΔH° - T.ΔS°

ΔG° = -3.583 kJ/mol - 263.3 K × 0.51379 kJ/mol.K

ΔG° = -138.9 kJ/mol

8 0
3 years ago
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