Answer:
we can use 100g of compounds as the basis.
Explanation:
Answer:
Two electrons each!
Explanation:
The question pretty much requires us to find the oxidation number of Zinc in the compound.
Zn3P2
Following oxidation number rules;
O.N of Zn3P2 = 0
.Since phosphorus has valence of 5, it needs three more electrons to achieve its octet state. Hence;
Oxidation number of P = -3
Let oxidation number of Zn = x
We have;
3x + 2 (-3) = 0
3x + (-6) = 0
3x = 6
x = 6/3 = 2
This means each zn electrons lost 2 electrons.
Alpha decay involves the loss of an alpha particle, aka a helium nucleus. This results in the mass number of the original element decreasing by 4 and the atomic number decreasing by 2. Assuming 23942u is uranium (92), the resulting element's atomic number is 90, making it thorium.
