Given:
128g sample of titanium
2808J of heat energy
specific heat of titanium is 0.523 J/ g °C.
Required:
Change in temperature
Solution:
This can be solved
through the equation H = mCpT
where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.
Plugging in the
values into the equation
H = mCpT
2808J = (128g) (0.523
J /g °C) T
T
= 41.9 °C
Answer:
<h2>0.92 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question we have
mass = 16.1 g
volume = 17.5 mL
We have the final answer as
<h3>0.92 g/mL</h3>
Hope this helps you
12 thousandth is the same as 0.012, so to put something in scientific notation you move the decimal point to the left or right until it is between the first two numbers. So:
Moving the decimal for 0.012 to between the first two numbers, we get: 1.2
For every move of the decimal place to get there, we divide/multiply by 10 each time. In this case, we multiply by 10 each time.
To get to 1.2, we had to move the decimal 2 times, so the answer is 1.2×10^-2
When you move the decimal to the right, the value of the power is negative, and when you move it to the left it is positive.
Three main radioactive elements are:
Uranium
Thorium
Radium
