Answer:
9 and 16
Step-by-step explanation:
let the two numbers are X and Y
X+Y=24
X^2-Y^2=144
solve simultaneously
Answer:

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:

Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:

Class 66 - 68:

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:


<em>See attachment for result of 1-VarStats</em>
Answer: 12/5 or 2 2/5
Step-by-step explanation: 7/2 - 11
/10
The probability that Jenny gets to choose lunch is 64% 0.64 (rounded) or 0.636.
Work:
Number of roses and carnations divided by the total number of flowers
<span>7/11 = 0.636 = 0.64 (rounded)
once again same answer
</span><span /><span>
</span>
Answer:
<em>Each classroom received 120 gifts and the hospital received 12 gifts</em>
Step-by-step explanation:
<u>Division As Evenly Distribution</u>
The first concept we manage when learning about divisions is how to distribute an amount N among m elements such as everyone receives the same amount.
If the nature of the problem allows distributing decimal portions of N, then every receiver gets exactly the same amount N/m.
But things are different when the division must be an integer number. For example, if we wanted to divide gifts, we cannot give partial gifts. So the correct division is a matter of the study of integer numbers.
If N is divisible by m, i.e. there is no remainder in the division, then each element will receive N/m gifts. But what if they are not divisible? We must divide and take the integer part of the division and discard the remainder
We want to divide 2,292 gifts to the school, where there are 19 classrooms. If we divide 2,292/19 we get 120 and a remainder of 12.
Answer. Each classroom received 120 gifts and the hospital received 12 gifts