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Marianna [84]
3 years ago
13

When 12 is added to a number the result is 32 less than 3 times a number. What is this number?

Mathematics
2 answers:
neonofarm [45]3 years ago
7 0
X - the number

x+12=3x-32 \\
x-3x=-32-12 \\
-2x=-44 \\
x=\frac{-44}{-2} \\
x=22

The number is 22.
seropon [69]3 years ago
4 0
Let the number = x
12 + x = 3x - 32
x = 3x - 44 Subtract 12 from both sides
-2x = -44 Subtract 3x from both sides
<span>x = 22 Divide by -2

SO THE ANSWER IS 22. HOPE THIS HELPS!!!!!!!</span>
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Step-by-step explanation:

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A farmer sells 8.7 kilograms of pears and apples at the farmer's market. 2 5 of this weight is pears, and the rest is apples. Ho
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Answer: 5.22kg

Step-by-step explanation:

From the question, a farmer sells 8.7 kilograms of pears and apples at the market. Of the pears and apples sold, 2/5 of this weight is pears, and the rest is apples. To calculate the kilograms of apple sold goes thus:

Total kilograms sold = 8.7kg

Fraction of pears weight = 2/5

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Since the kilograms of pears sold is , 3.48kg, to get the kilograms of apple sold, we subtract 3.48kg from 8.7kg. This will be:

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3 hours

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Maru [420]

Answer:

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Step-by-step explanation:

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We can rewrite our given integral as:

\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx

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Now, we will apply the sum rule of integrals as:

\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx

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Using common integral \int \frac{1}{x}dx=\text{ln}|x|, we will get:

9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx

Now, we will use power rule of integrals as:

9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx

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We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

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Therefore, our required integral would be 9\text{ln}|x|+2\sqrt{x}+x+C.

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