A gas may dissolve in a liquid. True False

An average, how many eggs does a female release each<br> cycle?

bagirrra123 [75]

Answer:

At birth, there are approximately 1 million eggs; and by the time of puberty, only about 300,000 remain. Of these, only 300 to 400 will be ovulated during a woman's reproductive lifetime. Fertility can drop as a woman ages due to decreasing number and quality of the remaining eggs.

Explanation:

Hope This Helps!!

5 0

3 years ago

Read 2 more answers

You draw back on the piston of a pump and the volume of air in the pump doubles. Which of the following happens?

ohaa [14]

Answer: The correct answer is Option C.

Explanation:

We are given a piston of a pump, which means that there is no loss of the air. and there is a change in pressure and volume but temperature of the system remains constant.

As, the pressure of the system increases, there will be more number of particles. So, the number of collisions per unit area will increase.

$\text{Number of collisions}\propto \text{Pressure}$

But in the question, volume gets doubled. So, the pressure will be determined by using Boyle's Law:

$P\propto \frac{1}{V}$

$V_2\rightarrow 2V_1$

where, $V_1\text{ and }V_2$ are the initial and final volume respectively.

Putting the change in volume in above equation, we get:

$P_2=\frac{1}{2V_1}\\\\P_2=\frac{1}{2}P_1$

where, $P_1\text{ and }P_2$ are the initial and final pressure respectively.

As, the pressure is reduced to half of the initial pressure. So, the number of collisions per unit area will also be reduced to one-half.

Hence, the correct answer is Option C.

5 0

3 years ago

Read 2 more answers

Please help with this

GenaCL600 [577]

1. Double-Replacement reactions

2. Decomposition

3. Combustion

4. Syntesis

5. Single replacement

<h3>Further explanation</h3>

Given

Chemical equations

Required

Type of reaction

Solution

1. 2AgNO₃ + MgCl₂ ⇒ 2AgCl + Mg(NO₃)₂

Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant

2. 2KBr⇒2K +Br₂

Decomposition

Single compound breaks down in to 2 or more products

3. C₃H₈ + 5O₂ ⇒ 4H₂O + 3CO₂

Combustion

Hydrocarbon and Oxygen reaction and form water and carbon dioxide

4. NaO + H₂O ⇒ NaOH

Syntesis

2 or more reactants combine to form a single product

5. Zn + CuCl₂ ⇒ZnCl₂ + Cu

Single replacement

One element replaces another element from a compound

6 0

3 years ago

Choose the stronger acid in each of the following pairs:H₂Se or H₃As

yarga [219]

H₃As is stronger acid than H₂Se.

The H-A bond strength typically determines the size of the "As" atom in an acid; the smaller the "As" atom, the stronger the H-A bond. In the Periodic Table, the atoms get bigger and the bonds get weaker as you advance down a row, strengthening the acids.

Any molecule or ion that may donate a proton—a Brnsted-Lowry acid—or establish a covalent bond with a pair of electrons—a Lewis acid—is regarded as an acid. The first class of acids are the Brnsted-Lowry acids, often known as proton donors.

The compound is referred to chemically as lysergic acid diethylamide, or LSD as it is more commonly known. Using it may lead you to have a distorted perception of reality and objects because it has a potent hallucinogenic effect. LSD has an effect known as tripping.

Aqueous solutions of acids with a pH lower than 8 are frequently referred to as "acids," even though the term "acid" technically only refers to the solute.

To learn more about acid visit:

brainly.com/question/14072179

#SPJ4

5 0

2 years ago

Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electr

Len [333]

Answer:

a. 1875 nm

b. 4051 nm

c. 1282 nm

These all are infrared electromagnetic radiation.

Explanation:

Our strategy here is to utilize the Rydberg equation for hydrogen atom electronic transition.

1/λ = Rh x (1/n₁² - 1/n₂²) where λ is the wavelength

Rh is Rydberg constant

n₁ and n ₂ are the energy levels ( n₁ < n₂ )

Now lets star the calculations.

a. n₁ = 3, n₂ = 4

1/λ = 1.097 x 10⁷ /m x (1/3² - 1/4²) = 5.333 x 10⁵/m

λ = 1/(5.333 x 10⁵ /m) = 1.875 x 10⁻⁶ m

Converting λ to nanometers:

1.875 x 10⁻⁶ m x (1 x10⁹ nm/m) = 1875 nm

b. n₁ = 4, n₂ = 5

1/λ = 1.097 x 10⁷ /m x (1/4² - 1/5²) = 2.468 x 10⁵/m

λ = 1/(2.468 x 10⁵/m) = 4.051 x 10⁻⁶ m

4.051 x 10⁻⁶ m x (1 x10⁹ nm/m) = 4051 nm

c. n₁ = 3, n₂ = 5

1/λ = 1.097 x 10⁷ /m x (1/3² - 1/5²) = 7801 x 10⁵/m

λ = 1/(7801 x 10⁵/m) = 1282 x 10⁻⁶ m

1282 x 10⁻⁶ m x (1 x10⁹ nm/m) = 1282 nm

All of these transitions fall in the infrared region of the spectrum.

8 0

3 years ago