The result is a line perpendicular to y=3x-2 This line has the following equation: y =mx + b, where m = slope
Remember that the product of the slopes of two perpendicular lines is always = -1 (or in other term one is the reciprocal inverse of the other) so the first slope = 3 and the sope perpendicular to 3 will be - 1/3. Then the new equation is y = - 1/3(x) + b How to calculate b? This line passes through (6, 8), that means (x=6 and y=8) . Plug these values in y = -1/3 (x)+b:3 8=(-1/3)(6) + b; 8= - 2 + b and b = 10 Te final equation is y = - 1/3.x+10 (answer A)
