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iragen [17]
3 years ago
6

What is the equation of a line that is perpendicular to y=3x-2 and passes through the point (6 8) ?

Mathematics
1 answer:
Scrat [10]3 years ago
8 0
The result is a line perpendicular to y=3x-2
This line has the following equation: y =mx + b, where m = slope

Remember that the product of the slopes of two perpendicular lines is always = -1 (or in other term one is the reciprocal inverse of the other) so the
first slope = 3 and the sope perpendicular to 3 will be - 1/3.
Then the new equation is y = - 1/3(x) + b
How to calculate b? This line passes through (6, 8), that
means (x=6 and y=8) . Plug these values in y = -1/3 (x)+b:3
 8=(-1/3)(6) + b; 
8= - 2 + b and b = 10
Te final equation is y = - 1/3.x+10 (answer A)
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8 0
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Read 2 more answers
I need help on this one
umka2103 [35]
You seem to have gotten m∠2. Remember that ∠1 and ∠2 are alternate interior angles, meaning they're both equal. Since they gave you m∠1 as being 26°, you now know the measure of ∠2.

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6 0
3 years ago
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3 0
2 years ago
This is my third time asking for helpppppppppp
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