Answer:
Ex(P) = -3.602 x 10^6 N/C
Explanation:
- q2 = 2.6 μC = the net charge on the conducting shell
- inner radius of conducting shell = a = 2.2 cm =0.022m
- outer radius of conducting shell = b = 4.5 cm = 0.045m
1) To get Ex(P), the value of the x-component of the electric field at point P, located a distance 8.8 cm along the x-axis from q1 ;
Ex(P) = k(q1+q2)/r^2
= 9 x 10^9 (-5.7 + 2.6) x 10^-6 /0.088^2
Ex(P) = -27.9 x 10^3/ 0.007744
Ex(P) = -3.602 x 10^6 N/C
Vf = Vi + at
Vf = 0 + (9.80)(4)
Vf = 39.2 m/s down
Hope a monkey breaks Arnold’s leg!
C. He could release the brakes.
Answer:
B, A, C, D
Explanation:
i hope it helps. im just kinda guessing.
good luck!°°°°°⁰⁰⁰⁰⁰₀₀₀₀₀oo00OO
Answer:
The 7.0-kg bowling ball with a speed of 6.0 meters per second
Explanation:
Momentum is p=mv
m = mass, v = velocity. (velocity is speed with direction)
1. 0.046-kg golf ball with a speed of 60.0 meters per second.
The mass is 0.046kg , velocty is 60.0
p= mv = 0.046 x 60 = 2.76kg
2. 7.0-kg bowling ball with a speed of 6.0 meters per second
Mass is 7kg, velocity = 6
p=mv = 7 x 6 = 42kg
The 7.0kg bowling ball has more momentum because 42 is greater than 2.76.