Answer:
λ = 3.4 × 10^18m
Explanation:using Rydberg equation:
1/λ = RH •Z^2[ (1/n1) - (1/n2) ]
RH = Rydberg constant = 2.18x 10^-18j)
n1 and n2 = energy levels (n2 >n1)
Z = atomic number = 4
Substitute
1/λ = 2.18x 10^-18• [ (1/3) - (1/5) }
λ = 3.4 × 10^18m
Answer:
The speed of the light signal as viewed from the observer is c.
Explanation:
Recall the basic postulate of the theory of relativity that the speed of light is the same in ALL inertial frames. Based on this, the speed of light is independent of the motion of the observer.
Relative to the movement of the building, a mass damper on the roof of an earthquake resistant building move in the opposite direction. The correct option is C.
<h3>What is mass damper?</h3>
Mass dampers absorbs the kinetic energy of the waves, converting them into the heat energy. This heat energy is dissipated to the hydraulic fluid.
The mass dampers used on roof of the buildings are called as the tuned mass dampers. They are also known as seismic dampers. When seismic wave strikes the building, it vibrates and sways. The kinetic energy of theses waves are absorbed by movement of the mass damper. The kinetic energy is converted to the heat energy which in turn is transmitted to the fluid.
Relative to the movement of the building, a mass damper on the roof of an earthquake resistant building move in the opposite direction.
Thus, the correct option is C.
Learn more about mass dampers.
brainly.com/question/14004102
#SPJ1
Answer:
metalloids
Explanation:
metalloids are also known as semiconductors. they are the ones that are between metals and non metals
Answer:
The formula i use is called, Product over Sum. Which means it is figured by their multiplied resistances divided by their sum. It is applied by pairs of known resistances. Starting with 20 and 30 Ohms, 600 is divided by 50. Using a quick mental calculation, the first pair has a resistance of 12 Ohms. Then, do that with 12 Ohms and 10 Ohms. 120 Ohms divided by 22. The answer is, about 5.5 Ohms. By this interesting development, we are reminded that resistances in parallel are effectively never more than the least one.
The students decide to assemble a convenient experiment and will run one amp through them all in parallel and measure their voltage. Watching the Amperage gauge on their teacher’s power supply. As one begins to turn it up to an Amp, another is watching its voltage till an Amp is perfectly applied. But as they carefully do that, watching the Amp gauge, another screams, their 10 Ohm resistor turns black and smokes as they were only pumping out 2 or 3 tenths of an Amp. What happened? What did they need, to make this simple experiment not so embarass-king?
Buy room air freshener?