Which of the following is not a function of protein?

Physics

2 answers:

Bess [88]2 years ago

5 0

Answer: I Believe The Answer Is A. Insulating The Body

Minchanka [31]2 years ago

3 0

Insulating the body is not a function of the protein.

Answer: Option A

<u>Explanation: </u>

The body is insulated with the help of protein, therefore, it is not a function of the protein. Protein makes the structure of the cell as the backbone. Protein specializes itself in structure to function as the enzymes.

They also serve as the secretion or production of the hormone which led to cell communication. Enzymes give the metabolic process and signaling of the cell are all function of the protein.

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The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, in

bezimeni [28]

1) Potential difference: 1 V

2) $V_b-V_a = -1 V$

Explanation:

When a charge moves in an electric field, its electric potential energy is entirely converted into kinetic energy; this change in electric potential energy is given by

$\Delta U=q\Delta V$

where

q is the charge's magnitude

$\Delta V$ is the potential difference between the initial and final position

In this problem, we have:

$q=4.80\cdot 10^{-19}C$ is the magnitude of the charge

$\Delta U = 4.80\cdot 10^{-19}J$ is the change in kinetic energy of the particle

Therefore, the potential difference (in magnitude) is

$\Delta V=\frac{\Delta U}{q}=\frac{4.80\cdot 10^{-19}}{4.80\cdot 10^{-19}}=1 V$

Here we have to evaluate the direction of motion of the particle.

We have the following informations:

- The electric potential increases in the +x direction

- The particle is positively charged and moves from point a to b

Since the particle is positively charged, it means that it is moving from higher potential to lower potential (because a positive charge follows the direction of the electric field, so it moves away from the source of the field)

This means that the final position b of the charge is at lower potential than the initial position a; therefore, the potential difference must be negative:

$V_b-V_a = - 1V$