We have,
(2y)^3 × y^-1
Simplify the term (2y)^3
= 8y^3 × y^-1
Now, multiply the terms with the same base y by adding their exponents.
Note: Using exponent product rule x^y × x^z = x^(y+z)
= 8y^{3+(-1)}
= 8y^(3-1)
= 8y^(3-1)
= 8y^2
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It's too short. Write at l<span>Remember that it's against our guidelines to copy content from other websites, books or any other material to which you don't own the rights to. We know you have the power to solve these problems on your own!</span>east 20 characters to explain it well
<span>Given:
∠PQS = 87°, and m∠SQR = 33° find </span>m∠PQR .<span>
m∠PQR
= m</span>∠PQS + m∠SQR
= 87° + 33°
= 120°
won't it be 3.2 because A square has four sides so you multiply 0.8 by 4
