Answer:
<em>102°</em>
Step-by-step explanation:
(3x - 12)° + (2x + 2)° = 180°
5x - 10 = 180 ⇒ x = 38
m∠A = (3x - 12)°
<em>m∠A</em> = (3×38 - 12)° = <em>102°</em>
To get the solution, we are looking for, we need to point out what we know.
<span>1. We assume, that the number 150 is 100% - because it's the output value of the task. </span>
<span>2. We assume, that x is the value we are looking for. </span>
<span>3. If 150 is 100%, so we can write it down as 150=100%. </span>
<span>4. We know, that x is 16% of the output value, so we can write it down as x=16%. </span>
5. Now we have two simple equations:
1) 150=100%
2) x=16%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
150/x=100%/16%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 16% of 150
150/x=100/16
<span>(150/x)*x=(100/16)*x - </span>we multiply both sides of the equation by x
<span>150=6.25*x - </span>we divide both sides of the equation by (6.25) to get x
<span>150/6.25=x </span>
<span>24=x </span>
x=24
<span>now we have: </span>
<span>16% of 150=24</span>
Mean: add up all numbers and divide by the number of data
12 + 12 + 7 + 5 + 10 + 16 = 62
62/6 = 10.333... (mean)
5,7,10,12,12,16
Find what’s in the middle
The medium is 11
Given that the subway stations are 930 m apart, the train have to be accerelated for half the distance and then decerelated for the rest of the distance.
Recall that the distance travelled by an object with an initial velocity, u, for a period of time, t, at an accereration, a, is given by

But, we assume that the train accelerates from rest, thus

The maximum speed is attained at half the center of the distance between subway stations (i.e. at distance = 465 m).
Thus, maximum speed = distance / time = 465 / 23.12 = 20.11 m/s.