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stealth61 [152]
3 years ago
15

-17 = 1 + 6n + 3n what is n

Mathematics
2 answers:
tino4ka555 [31]3 years ago
6 0
N= -2
First add 6n + 3n = 9n and then subtract 1
Mashcka [7]3 years ago
4 0

Answer:

n = -2

Step-by-step explanation:

-17 = 1 + 6n + 3n

Combine like terms

-17 = 1 +9n

Subtract 1 from each side

-17-1 = 1-1+9n

-18 = 9n

Divide each side by 9

-18/9 = 9n/9

-2 =n

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Vedmedyk [2.9K]
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4 0
3 years ago
Write an equation in slope intercept form thag passes through (4,-4) and is parallel to 3+4x=2y-9
uysha [10]

The original line is

4x - 2y = -12

The parallel lines will all be

4x - 2y = constant

and the constant is given by the point directly:

4x - 2y = 4(4) - 2(-4) = 24

2y = 4x - 24

y = 2x - 12

Answer: y = 2x - 12


7 0
3 years ago
Read 2 more answers
Please help
Varvara68 [4.7K]

Answer:

$6 = cost of small box

$8 = cost of large box

Step-by-step explanation:

Let s = cost of small box

     l  = cost of large box

(1)    12s + 3l = 96            (2)     6s + 6l = 84

    Multiply by -2                    <u> -24s - 6l = -192</u>

                                                -18s   = - 108

                                                     s = $6 = cost of small box

      12(6) + 3l = 96

         72 + 3l = 96

                 3l = 24

                   l = $8 = cost of large box

7 0
3 years ago
Of the entering class at a​ college, ​% attended public high​ school, ​% attended private high​ school, and ​% were home schoole
Veronika [31]

Answer:

(a) The probability that the student made the​ Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

<em>A</em> = a student attended public high school

<em>B</em> = a student attended private high school

<em>C</em> = a student was home schooled

<em>D</em> = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})

Compute the probability that the student made the​ Dean's list as follows:

P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)

         =(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655

Thus, the probability that the student made the​ Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D)}

             =\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

P(C^{c}|D^{c})=1-P(C|D^{c})

               =1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0
3 years ago
Solve for s. 5/9s+13/9s=24
g100num [7]
Solving for s, I get s = 12. 
5 0
3 years ago
Read 2 more answers
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